[英]How can I compile JS and JSON together?
I have a project where the prod machine specs are low so I'm trying something new and trying Gulp to compile everything into one compressed js file.我有一个项目,其中 prod 机器规格很低,所以我正在尝试一些新的东西并尝试 Gulp 将所有内容编译成一个压缩的 js 文件。
I have a config.json
that's being used by main.js
.我有一个
config.json
正在使用的main.js
。 What does my gulpfile.js
has to look like in order to turn those two files into one js file?为了将这两个文件变成一个 js 文件,我的
gulpfile.js
必须是什么样子?
You may declare a variable in JS to contain the JSON data as per following example您可以按照以下示例在JS中声明一个变量以包含 JSON 数据
var arr = [
{
data1: 'mydata01',
data2: 'mydata02',
},
{
data3: 'mydata03',
data4: 'mydata04',
}
]
But this defeats the spirit and purpose of JSON which is primarily for exchanging of Data between two entities (two webpages, client-server, webpage-database, etc).但这违背了 JSON 的精神和目的,主要用于在两个实体(两个网页、客户端-服务器、网页-数据库等)之间交换数据。 This technique will make the data hardcoded in the JS with lesser flexibility to change the data dynamically.
这种技术将使JS中的数据硬编码,动态更改数据的灵活性较低。
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