排序时小写和大写字母分开处理

Question

While sorting String field

• If field is empty then it should go at the top in desc and at the bottom in asc (This is working fine)
• For Integer behaviour is fine (It considers null/undefined values and do sorting)

Only problem is with 'Case sensitivity'

• It should treat 'rosy' And 'Rosy' as same and display them on after another

 function dynamicsort(property,order) { var sort_order = 1; if(order === "desc"){ sort_order = -1; } return function (a, b){ //check if one of the property is undefined if(a[property] == null){ return 1 * sort_order; } if(b[property] == null){ return -1 * sort_order; } // a should come before b in the sorted order if(a[property] < b[property]){ return -1 * sort_order; // a should come after b in the sorted order }else if(a[property] > b[property]){ return 1 * sort_order; // a and b are the same }else{ return 0 * sort_order; } } } let employees = [ { firstName: 'John11', age: 27, joinedDate: 'December 15, 2017' }, { firstName: 'john22', lastName: 'rosy', age: 44, joinedDate: 'December 15, 2017' }, { firstName: 'SSS', lastName: 'SSSS', age: 111, joinedDate: 'January 15, 2019' }, { firstName: 'Ana', lastName: 'Rosy', age: 25, joinedDate: 'January 15, 2019' }, { firstName: 'Zion', lastName: 'Albert', age: 30, joinedDate: 'February 15, 2011' }, { firstName: 'ben', lastName: 'Doe', joinedDate: 'December 15, 2017' }, ]; console.log("Object to be sorted"); console.log(employees); console.log("Sorting based on the lastName property") console.log(employees.sort(dynamicsort("lastName","desc"))); console.log("Sorting based on the lastName property") console.log(employees.sort(dynamicsort("lastName","asc")));

Answer 1

You could use localeCompare() ( docs ) to compare the properties if they are strings.

Here is a simple example based on your code. There are other possible improvements but I don't want to change your original code too much, so I'm just showing one way you could use localeCompare() .

function dynamicsort(property,order) {
    var sort_order = 1;
    if(order === "desc"){
        sort_order = -1;
    }
    return function (a, b){
        //check if one of the property is undefined
        if(a[property] == null){
                return 1 * sort_order;
        }
        if(b[property] == null){
                return -1 * sort_order;
        }
        // if both properties are strings use localeCompare
        if (typeof a[property] === "string" && typeof b[property] === "string") {
            return a[property].localeCompare(b[property]) * sort_order;
        }
        // a should come before b in the sorted order
        if(a[property] < b[property]){
                return -1 * sort_order;
        // a should come after b in the sorted order
        }else if(a[property] > b[property]){
                return 1 * sort_order;
        // a and b are the same
        }else{
                return 0 * sort_order;
        }
    }
}

Answer 2

transform both strings to lower case or uppercase before the sort.