Laravel - 如何使用关系列中的任何内容创建搜索过滤器

Question

I'm trying to make a query where returns me the results, based on a request word, but I have to filter with the relationship columns as well. Example:

Payment::byUnity($unityId)
            ->with(['contract:id,nome,sigla'])
            ->latest('id')
            ->where('id', 'LIKE', '%' . $request->input('search') . '%')
            ->orWhere('name', 'LIKE', '%' . $request->input('search') . '%')
            ->orWhere('contract.name', 'LIKE', '%' . $request->input('search') . '%')
            ->orWhere('contract.description', 'LIKE', '%' . $request->input('search') . '%')
            ->paginate(15)

How can I filter the "contract.name" on the query? Because the way of the example returns me error. Thanks in advance!

Answer 1

You can do

Payment::byUnity($unityId)
            ->with(['contract:id,nome,sigla'])
            ->latest('id')
            ->where('id', 'LIKE', '%' . $request->input('search') . '%')
            ->orWhere('name', 'LIKE', '%' . $request->input('search') . '%')
            ->orWhereHas('contract', function($query) use ($request) {
                return $query->where('name', 'LIKE', '%' . $request->input('search') . '%')
                ->orWhere('description', 'LIKE', '%' . $request->input('search') . '%');
            }
            ->paginate(15)

NOTE: You must have proper relationships set up for this query to work.