如何在 python 的列表中将一个元素划分为另一个元素

Question

There is a couple of lists and I want to write a code thats input as DIVIDE,(fruit name) and the output is that fruits datas(5th lement/3rd element) from its list.For example one of the list is ['apple', 'a', 147, 457, 66, 119, 21, 6, 8] and the output is 0.26!

fruits = [['apple', 'a', 147, 457, 66, 119, 21, 6, 8], ['banana', 'b', 131, 454, 53, 108, 19, 0, 20], ['orange', 'o', 124, 454, 54, 110, 20, 2, 29], 21]
command, name = input().split()
def count_machine(command, name):
    if command == "DIVIDE" :

        for fru in fruits:
            if name == fru[0]:
                result = [fru[5] / fru[3]]
                return result

result = count_machine(command, name)
if type(result) == float:
    print("%.2f" % result)

Where am i doing wrong,isn't it possible to divide [fru[5] / fru[3]] two elements like this?

Answer 1

Remove [] from result

if name == fru[0]: 
      result = [fru[5] / fru[3]]

Should be

  if name == fru[0]: 
      result = fru[5] / fru[3]

As your code make result a list not a float

Answer 2

The result returned is a list. So, instead of checking for float type, do this to capture the float value-

if type(result) == list:
    print("%.2f" % result[0])