[英](Rust- JSON) How to convert &str to JSON response in rust?
Hello I have a &str type variable.您好,我有一个 &str 类型的变量。 How can I convert it to json?如何将其转换为 json? for example I have &str例如我有 &str
{"index":0,"name":"AB/CDE/FG/402/test_int4","sts":"on","time":"2021-06-05 03:28:24.044284300 UTC","value":8}
How can I convert this to json如何将其转换为 json
{
"index": 0,
"name": "AB/CDE/FG/402/test_int4",
"sts": "on",
"time": "2021-06-05 03:28:24.044284300 UTC",
"value": 8
}
is there anything like python json.loads() method available or something equivalent can be done in rust?是否有类似 python json.loads() 方法可用或可以在 rust 中完成类似的方法?
I dont know anything builtin, but this package can do it:我什么都不知道,但是这个 package 可以做到:
use tinyjson::{JsonParseError, JsonValue};
fn main() -> Result<(), JsonParseError> {
let s = r#"
{
"index":0,
"name":"AB/CDE/FG/402/test_int4",
"sts":"on",
"time":"2021-06-05 03:28:24.044284300 UTC",
"value":8
}
"#;
let m: JsonValue = s.parse()?;
println!("{:?}", m);
Ok(())
}
Result:结果:
Object({
"value": Number(8.0),
"index": Number(0.0),
"name": String("AB/CDE/FG/402/test_int4"),
"time": String("2021-06-05 03:28:24.044284300 UTC"),
"sts": String("on")
})
There's a misconception here.这里有一个误解。 JSON is a serialization format, its always a string. JSON 是一种序列化格式,它始终是一个字符串。 Your two blocks are both JSON and functionally identical.你的两个块都是 JSON 并且功能相同。 What json.loads()
is deserialize it into a value that can be accessed and manipulated natively. json.loads()
将其反序列化为可以本地访问和操作的值。
You probably want to use a serde_json::Value
if you want to this JSON to be used generically.如果您想将此 JSON 用于一般用途,您可能需要使用serde_json::Value
。
use serde_json::Value;
fn main() {
let input = r#"{"index":0,"name":"AB/CDE/FG/402/test_int4","sts":"on","time":"2021-06-05 03:28:24.044284300 UTC","value":8}"#;
let mut object: Value = serde_json::from_str(input).unwrap();
if let Some(name) = object.get_mut("name") {
*name = "new name".into();
}
println!("{}", object);
}
{"index":0,"name":"new name","sts":"on","time":"2021-06-05 03:28:24.044284300 UTC","value":8}
Or, its typical to create a structure that reflects what the JSON is expected to be and deserialize into that type via serde
:或者,通常创建一个结构来反映 JSON 预期的内容,并通过serde
反序列化为该类型:
use serde::{Deserialize, Serialize};
#[derive(Serialize, Deserialize, Debug)]
struct Data {
index: i32,
name: String,
sts: String,
time: String,
value: i32
}
fn main() {
let input = r#"{"index":0,"name":"AB/CDE/FG/402/test_int4","sts":"on","time":"2021-06-05 03:28:24.044284300 UTC","value":8}"#;
let mut object: Data = serde_json::from_str(input).unwrap();
object.name = "new name".to_string();
println!("{:#?}", object);
}
Data {
index: 0,
name: "new name",
sts: "on",
time: "2021-06-05 03:28:24.044284300 UTC",
value: 8,
}
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