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ANSI C 中的合并排序算法

[英]Merge sort algorithm in ANSI C

I'm learning ANSI C and for a class I have to implement a merge sort algorithm in it.我正在学习 ANSI C,对于 class,我必须在其中实现合并排序算法。 I'm following the book's guide.我正在按照本书的指南进行操作。 But, for some reason I can't have it working.但是,由于某种原因,我无法让它工作。

Only two digits from my list got in the right position.我的列表中只有两位数字在正确的 position 中。 And for the others, new digits are created.而对于其他人,则创建了新的数字。 I have no idea why this happens, I think it is the way I create the temp arrays L and R (I'm using 1.0 / 0.0 to set the last element to +INFINITY ).我不知道为什么会发生这种情况,我认为这是我创建临时 arrays LR的方式(我使用1.0 / 0.0将最后一个元素设置为+INFINITY )。 But I'm not sure if that is the reason.但我不确定这是否是原因。

Here is my code so far:到目前为止,这是我的代码:

/* C program for Merge Sort */
#include <stdio.h>
#include <stdlib.h>


void printArray(int A[], int size) {
    int i;
    for (i = 0; i < size; i++)
        printf("%d ", A[i]);
    printf("\n");
}

void merge(int arr[], int l, int m, int r) {
    int i, j, k;
    int n1 = m - l + 1;
    int n2 = r - m;

    int L[n1 + 1], R[n2 + 1];

    for (i = 1; i <= n1; i++) {
        L[i] = arr[l + i - 1];
    }
    for (j = 1; j <= n2; j++) {
        R[j] = arr[m + j];
    }

    L[n1 + 1] = 1.0 / 0.0;
    R[n2 + 1] = 1.0 / 0.0;
    i = 1;
    j = 1;

    for (k = l; k <= r; k++) {
        if (L[i] <= R[j]) {
            arr[k] = L[i];
            i++;
        } else {
            arr[k] = R[j];
            j++;
        }
    }
    
    // If I delete this the code stop "working". Why???
    while (i < k && k < i) {
            i++;
    }
}

void mergeSort(int arr[], int left, int right) {

    if (left < right) {
        int middle = left + (right - left) / 2;

        mergeSort(arr, left, middle);
        mergeSort(arr, middle + 1, right);

        merge(arr, left, middle, right);
    }
}


int main() {
    int arr[] = { 12, 11, 13, 5, 6, 7 };
    int arr_size = sizeof(arr) / sizeof(arr[0]);

    printf("Given array is \n");
    printArray(arr, arr_size);

    mergeSort(arr, 0, arr_size - 1);

    printf("\nSorted array is \n");
    printArray(arr, arr_size);
    return 0;
}

Also, for some reason beyond my humble understanding when i delete the while block, that does nothing apparently, the code stops working.此外,由于某些原因超出了我的理解,当我删除while块时,显然没有任何作用,代码停止工作。 Can someone give me a light on this?有人可以告诉我这个吗?

The problem lies in your attempt to use 'infinity'.问题在于您尝试使用“无穷大”。 Your data are integer values, and there is no representation of infinity in the integral types.您的数据是integer值,整数类型中没有无穷大的表示。

To set a "maximum possible value," use the pre-defined INT_MAX constant.要设置“最大可能值”,请使用预定义的INT_MAX常量。 So, replace the following lines:因此,替换以下行:

    L[n1 + 1] = 1.0 / 0.0;
    R[n2 + 1] = 1.0 / 0.0;

with:和:

    L[n1 + 1] = INT_MAX;
    R[n2 + 1] = INT_MAX;

Also, as you access the [n1 + 1] and [n2 + 1] elements of the L and R arrays, you will need to increase the size of each of those arrays by one (arrays in C start at zero and end at 'n' - 1). Also, as you access the [n1 + 1] and [n2 + 1] elements of the L and R arrays, you will need to increase the size of each of those arrays by one (arrays in C start at zero and end at ' n' - 1)。 Like so:像这样:

    int L[n1 + 2], R[n2 + 2]; // So we can use the `... + 1` elements.

With these changes, the code you posted works (even removing the strange while loop at the end of your merge function).通过这些更改,您发布的代码可以正常工作(甚至在merge函数末尾删除奇怪的while循环)。


Note: Although your 1.0/0.0 does produce a floating point representation of infinity, attempting to cast/convert that value to an int produces Undefined Behaviour.注意:尽管您的1.0/0.0确实会产生无穷大的浮点表示,但尝试将该值强制转换/转换为int会产生未定义的行为。 See: What is the result of casting float +INF, -INF, and NAN to integer in C?请参阅:在 C 中将浮点 +INF、-INF 和 NAN 转换为 integer 的结果是什么?

As to why that strange while loop was 'required' to make your code (not quite) work: Well, once undefined behaviour is invoked, anything can happen (including the summoning of Nasal Demons from the ether).至于为什么“需要”那个奇怪的while循环来让你的代码(不完全)工作:好吧,一旦调用了未定义的行为,任何事情都可能发生(包括从以太中召唤鼻恶魔)。 See: Undefined, unspecified and implementation-defined behavior请参阅:未定义、未指定和实现定义的行为

There is my merge sort algorithm, and the function returns the number of inversions.有我的归并排序算法,function 返回倒数。

int merge(int array[], int tempArray[],
          size_t left, size_t middle1, size_t middle2, size_t right)
{
    size_t leftIndex = left, rightIndex = middle2, combinedIndex = left;
    int inversions = 0;

    while (leftIndex <= middle1 && rightIndex <= right)
    {
        if (array[leftIndex] <= array[rightIndex])
        {
            tempArray[combinedIndex++] = array[leftIndex++];
        }
        else
        {
            tempArray[combinedIndex++] = array[rightIndex++];
            inversions += middle2 - leftIndex;
        }
    }

    while (leftIndex <= middle1)
    {
        tempArray[combinedIndex++] = array[leftIndex++];
    }

    while (rightIndex <= right)
    {
        tempArray[combinedIndex++] = array[rightIndex++];
    }

    for (size_t i = left; i <= right; i++)
    {
        array[i] = tempArray[i];
    }

    return inversions;
}
int mergeSort(int array[], int tempArray[], size_t low, size_t high)
{
    return low < high ? mergeSort(array, tempArray, low, (low + high) / 2) + mergeSort(array, tempArray, (low + high) / 2 + 1, high) + merge(array, tempArray, low, (low + high) / 2, (low + high) / 2 + 1, high) : 0;
}
int sort(int array[], size_t length)
{
    int *tempArray = (int *)malloc(sizeof(int) * length);
    return mergeSort(array, tempArray, 0, length - 1);
}

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