如何在 python 中出现 keyerror 异常时继续尝试阻止

Question

    try:
        key1 = val1
        key2 = val2
        key3 = val3
    except KeyError:
        pass
    finally:
        createTask()

in the above example, that createTask() runs in loop and keys changes for every run, how to continue to key2 if there is KeyError at key1 for a particular run?

Answer 1

Maybe that will do the job:

for key, val in zip([k1, k2, k3], [v1, v2, v3]):
    try:
        key = val
    except KeyError:
        pass
    finally:
        createTask()

Answer 2

Since you simply pass on KeyError, you can use dict get to avoid triggering KeyError . Then you will simply have to make sure that createTask() is smart enough to detect this condition.

    key1 = your_dict.get(val1, None)
    key2 = your_dict.get(val2, None)
    key3 = your_dict.get(val3, None)
    createTask()