[英]How do I only inherit some variables from a super class in Python
I am trying to make a subclass, Square, from a superclass, Shape.我正在尝试从超类Shape创建一个子类Square。
class Shape :
def __init__ (self, x, y) :
self.x = x
self.y = y
self.description = "This shape has not been described yet"
def area (self) :
return self.x * self.y
def describe (self, text) :
self.description = text
I have tried我努力了
class Square (Shape) :
def __init__ (self, x) :
self.x = x
self.y = x
self.description = "This shape has not been described yet"
which seems to work, but the only thing that actually changes in Square is self.y = x, so I wonder if I could do the same thing without having to write self.x and self.description again.这似乎可行,但 Square 中唯一真正改变的是 self.y = x,所以我想知道是否可以在不必再次编写 self.x 和 self.description 的情况下做同样的事情。
(I tried doing something like this: (我试着做这样的事情:
class Square (Shape) :
def __init__ (self, x) :
self.y = x
super().__init__()
but, when I create a Square object, a type error occurs: TypeError: init () missing 2 required positional arguments: 'x' and 'y')但是,当我创建 Square object 时,出现类型错误:TypeError: init () missing 2 required positional arguments: 'x' and 'y')
A Square
is a Shape
whose x
and y
are the same. Square
是x
和y
相同的Shape
。 Hence:因此:
class Square(Shape):
def __init__(self, x):
super().__init__(x, x)
You just need to call Shape.__init__(self, x, y)
with your x
as both the x
and y
parameters.您只需要使用x
作为x
和y
参数调用Shape.__init__(self, x, y)
。
Just call the super function inside __init__
.只需在__init__
中调用超级 function 即可。 Put both the arguments equal to x
.将 arguments 都设为x
。
class Square(Shape):
def __init__(self, x):
super().__init__(x, x)
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