在 do-while 循环中输入不适用于扫描仪 class

Question

In the do-while loop,the code is not taking input after first case. it gets terminated after taking the input and does not performs do-while loop properly.what is wrong with z=sc.nextLine(){in the while loop} or Scanner class? PS: I also tried with Scanner sc=new Scanner("System.in"); but the code still didn't work. Any other alternative than parseInt()?

OUTPUT COMING: size of stack? 5 1.PUSH 2.POP 3.Display 1 number for push? 19 continue? after continue,code gets terminated

Please Help.

class stak{
   int tos=-1;
   int size;
   int a[];
   
   stak(int l){
       size=l;
       tos=-1;
       a=new int[l];
   }
   void push(int x){
       if(tos==size-1){
           System.out.println("Stack Overflow");
       }
       else{
           a[++tos]=x;
       }
   }
   void pop(){
       if(tos<0){
           System.out.println("Stack Underflow");
       }
       else{
           System.out.println(a[tos--]);
       }
   }

   void display(){
       if(tos>=0){
           for(int i=tos;i>=0;--i){
               System.out.println(a[i]);
           }
       }
       else
       System.out.println("Stack is Empty");
   }

}

public class stack{
   public static void main(String args[]){
      Scanner sc=new Scanner(System.in);
      System.out.println("size of stack?");
      int n=sc.nextInt();
      stak s1=new stak(n);
      String z;
      do{
      System.out.println("1.PUSH");
      System.out.println("2.POP");
      System.out.println("3.Display");
      int ch=sc.nextInt();
      
      switch(ch){
           case 1 : System.out.println("number for push?");
                   int p=sc.nextInt();
                   s1.push(p);
                   break;
                   case 2 : System.out.println("POP!");
                   s1.pop();
                   break;
                   case 3 : System.out.println("Display!");
                   s1.display();
                   break;
                   default: System.out.println(" OOPS! owner says only take input as: 1,2,3");
                   break;
      }
     System.out.println("continue?");
    z=sc.nextLine(); 
   }while(z.equals("yes")|| z.equals("y"));
   sc.close();
}
}


 [1]: https://i.stack.imgur.com/BHZQO.png

Answer 1

The problem is with the scanner class. Because when you use call z=sc.nextLine(); this call first take the input from the line where you enter the number to push into the stack because int p=sc.nextInt(); this line only take one integer but does not finish the whole line.

So you can manually finish the line by adding a sc.nextLine() before taking the input for yes or no. By adding the extra nextLine() will finish the current line when you inter the integer.

import java.util.Scanner;

class stak{
    int tos=-1;
    int size;
    int a[];
    
    stak(int l){
        size=l;
        tos=-1;
        a=new int[l];
    }
    void push(int x){
        if(tos==size-1){
            System.out.println("Stack Overflow");
        }
        else{
            a[++tos]=x;
        }
    }
    void pop(){
        if(tos<0){
            System.out.println("Stack Underflow");
        }
        else{
            System.out.println(a[tos--]);
        }
    }
 
    void display(){
        if(tos>=0){
            for(int i=tos;i>=0;--i){
                System.out.println(a[i]);
            }
        }
        else
        System.out.println("Stack is Empty");
    }
 
 }
 
 public class stack{
    public static void main(String args[]){
       Scanner sc=new Scanner(System.in);
       System.out.println("size of stack?");
       int n=sc.nextInt();
       stak s1=new stak(n);
       String z;
       do{
       System.out.println("1.PUSH");
       System.out.println("2.POP");
       System.out.println("3.Display");
       int ch=sc.nextInt();
       switch(ch){
            case 1 : System.out.println("number for push?");
                    int p=sc.nextInt();
                    s1.push(p);
                    break;
                    case 2 : System.out.println("POP!");
                    s1.pop();
                    break;
                    case 3 : System.out.println("Display!");
                    s1.display();
                    break;
                    default: System.out.println(" OOPS! owner says only take input as: 1,2,3");
                    break;
       }
      System.out.println("continue?");
      sc.nextLine();
      z=sc.nextLine(); 
    }while(z.equals("yes")|| z.equals("y"));
    sc.close();
 }
 }

Hope this will help you. Other wise you can counter this issue by using BufferReader