将列表元组的列表写入 CSV

Question

I have the following variable:

data = [(['a', 'b', '3'], ['c', 'a', 'r']),
        (['*', '[', 'e'], ['33', 'gh', 'ew']),
        (['23^', 're#', '4$'], ['tr', 'fF', '5%'])]

I want to write data into a CSV file as follows:

a c
b a
3 r

* 33
[ gh
e ew

23^ tr
re# fF
4$ 5%

Note that after each iteration I have a black space in between.

---

I tried:

import csv 
with open ('train.csv', 'w') as out:
    writer = csv.writer(out)
    for row in dataset:
        writer.writerows(row)

But does not work properly.

Answer 1

Since this format doesn't conform to CSV rules you can just use regular string formatting to write the lines. The one trick is in the handling of the blank line separator. Assuming you don't want an extra blank line at the bottom of the output file, you can get a bit creative. Write the separator before writing each group, but start with a blank string and switch it to the real separator after the first write.

data = [(['a', 'b', '3'], ['c', 'a', 'r']),
        (['*', '[', 'e'], ['33', 'gh', 'ew']),
        (['23^', 're#', '4$'], ['tr', 'fF', '5%'])]

with open("test.txt", "w") as file:
    group_sep = "" # group separator written first to avoid extra blank
                   # line at end of file.
    for group1, group2 in data:
        file.write(group_sep)
        group_sep = "\n"
        for cell1, cell2 in zip(group1, group2):
            file.write(f"{cell1} {cell2}\n")

Answer 2

This should get it done.

data = [(['a', 'b', '3'], ['c', 'a', 'r']),
        (['*', '[', 'e'], ['33', 'gh', 'ew']),
        (['23^', 're#', '4$'], ['tr', 'fF', '5%'])]


with open('train.txt','w') as f:
    
    for x in  [tuple(zip(x[0],x[1])) for x in data]:
        for r in x:
            f.write(' '.join(r) + '\n')
        f.write('\n')