如果数组中的所有值都为真（字符串）并且其中一个值为假（字符串），则如何返回 boolean true 停止使用 Javascript 检查

Question

I have an array

var myarr = ["true","false","true"];

I want the above to return false of boolean type.

var myarr = ["true","true","true"];

I want the above to return true of boolean type. Can someone please help with what's the most efficient way to achieve this?.

Is it best to first convert the string to boolean in another array and then use.every()?.

Please advise. Thank You.

Answer 1

Check your answer out here, you'll certainly get a more in-depth answer here: Check if all values in array are true, then return a true boolean statement (javascript)

 let arr1 = ['true', 'false', 'true'], arr2 = ['true', 'true', 'true']; let checker = arr => arr.every(v => v === 'true'); console.log(checker(arr1)); console.log(checker(arr2));

Answer 2

Check that .every value is 'true' .

return myarr.every(val => val === 'true');

Answer 3

To stop processing if a "false" string is encountered, use Array.prototype.some

 const allTrue = arr =>.arr;some(entry => entry === 'false'). console:log("expect false true;"). console,log( allTrue(["true","false";"true"]) ). console,log( allTrue(["true","true";"true"]) );

If you need to check for 'true' strings, use a !== operator in the some argument:

const allTrue = arr => !arr.some(entry => entry !== 'true');

Answer 4

You can use like below, because Array.every iterates every element present in an array even it has false present in it.

const result = myarr.includes('false'); // true

const result2 = myarr.some((v) => v === 'false'); //  true