[英]How to convert specific CURL request to Python
I have the following Curl request:我有以下 Curl 请求:
curl -v --location --request POST 'http://127.0.0.1:8080/abc' \--header 'Content-Type: application/json' \--data-raw '{data}'
I tried using pycurl and requests command.我尝试使用 pycurl 和 requests 命令。 Also tried to put headers but it was of no use.
还尝试放置标题,但没有用。
My tried code:我试过的代码:
requests = "curl -v --location"
a = "http://127.0.0.1:8080/abc"
headers = {'Content-Type': 'application/json'}
r = requests.post(url=a, headers= headers , params=data)
Is this works?这行得通吗? https://curl.trillworks.com/
https://curl.trillworks.com/
import requests
headers = {
'Content-Type': 'application/json',
}
data = '{data}'
response = requests.post('http://127.0.0.1:8080/abc',
headers=headers,
data=data)
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