从字符串 python 库中提取 substring

Question

I have a string

string = 'Ph no. : 999999999 | year: 2021 | class no.: 10Type: 2-A | S-no. : dfwef | Name : dfwf'

Using regular expression python I want to extract Type. Output I want in this case is 2-A.

I have tried is

import re
type = re.findall(r'Type: \d*-', string)
print(type)

I have multiples strings of this type and i want to extract code text between 'Type:' and '|'.

Answer 1

This should give you the needed result if Type contains only one number, '-', and a letter

import re

string = 'Ph no. : 999999999 | year: 2021 | class no.: 10Type: 2-A | S-no. : dfwef | Name : dfwf'

type_str = re.search('(Type:\s\d+-\w+)', string).group()
print(type_str)

Type: 2-A

Or if you want to extract only the 2-A

import re

string = 'Ph no. : 999999999 | year: 2021 | class no.: 10Type: 2-A | S-no. : dfwef | Name : dfwf'

type_str = re.search('(Type:\s\d-\w)', string).group()
print(type_str.split(': ')[1])

2-A

And finally as requested to extract any text from Type: to |it will be

import re

string = 'Ph no. : 999999999 | year: 2021 | class no.: 10Type: 10 X-ASFD 34 10 | S-no. : dfwef | Name : dfwf'

type_str = re.search('Type:\s(.*?\|)', string).group()
print(type_str.split(': ')[1].replace('|',''))

10 X-ASFD 34 10

Answer 2

Use regex '(?<=Type: )[\w-]+'

• (?<=Type: ) will extract everything after Type:
• [\w-]+ will extract only digits , words and -

import re
re.findall(r'(?<=Type: )[\w-]+',string)
>> ['2-A']