如何根据最小绝对时间差编写查询以连接两个表？

Question

I need help writing a MySQL query to do a matching with the tables below. So far my query looks like this:

SELECT event.id, event.eventid, upload.uploadid
FROM event
LEFT JOIN upload
ON(event.id = upload.id and event.timestamp <= upload.timestamp);

The second condition in my join, event.timestamp <= upload.timestamp , is a placeholder until I can figure out a boolean expression (or something else) to get the desired result. I'm lost on how to write a statement to join based on minimum absolute time difference. The tables have the following structure:

Event table

id	eventid	timestamp
u1	event1	2020-01-01 01:30:00
u1	event2	2020-01-01 01:45:00
u2	event1	2020-01-01 05:30:00
u2	event2	2020-01-01 05:39:00

Upload table

id	uploadid	timestamp
u1	upload1	2020-01-01 01:30:00
u1	upload2	2020-01-01 02:30:00
u2	upload1	2020-01-01 05:30:00
u2	upload2	2020-01-01 05:35:00

The query needs to match every event in the event table to the closest upload from that respective user.

The desired result of the query is:

u1 event1 upload1
u1 event2 upload1
u2 event1 upload1
u2 event2 upload2

EDIT: The following query produced the the desired result:

SELECT e.id, e.eventid, 
        (SELECT u.uploadid
        FROM upload u
        WHERE (u.id = e.id and u.timestamp < e.timestamp)
        ORDER BY ABS(TIMESTAMPDIFF(second, u.timestamp, e.timestamp))
        LIMIT 1) 
FROM event e;

Answer 1

If you only want the uploadid , then I would suggest a correlated subquery:

SELECT e.*,
       (SELECT u.uploadid
        FROM upload u
        WHERE u.id = e.id
        ORDER BY ABS(TIMESTAMPDIFF(second, e.timestamp, u.timestamp))
       ) as uploadid
FROM event e;