如何使用 CSS 选择器来检索使用 BeautifulSoup 的特定链接？

Question

Im using python for scraping the following page: alfabeta.surge.sh and i would like to get the link in (#home1 > div:nth-child(10) > table:nth-child(29) > tbody > tr:nth-child(1) > td:nth-child(3) > a )

Actually im doing this:

import bs4, requests
res = requests.get('https://alfabeta.surge.sh/')
soup = bs4.BeautifulSoup(res.text, 'html.parser')
soup.find_all('a')[23].attrs.get('href')

But if the position of the change i cant download the content

Answer 1

You will need to make some assumptions about what is most likely to remain constant, and then review over time. For example, I might assume you want the 3rd column td 's child a tag href , from the table which is the first following the div with containing the string Catálogo Actualizaciones . One css pattern for that would be as follows:

import requests
from bs4 import BeautifulSoup as bs

r = requests.get('https://alfabeta.surge.sh/')
soup = bs(r.text, 'lxml')
print(soup.select_one('div:-soup-contains("Catálogo Actualizaciones") ~ table td:nth-child(3) > a')['href'])