如何在两个条件下，其中一个可以是多个值中的一个

Question

I want to check that:

1. if the state is true and the connection type is not 2 or 6 then do something.

2. if state is false and connection type is either 2 or 6 then do something else.

I have the following if statements but at points it is using the wrong code:

async setWiFiConnection(state){
        try{
            var connType = await driver.getNetworkConnection();
            if(state == true && connType != 2 && connType != 6){
                await driver.toggleWiFi();
            }else if(state == false && connType == 2 || connType == 6){
                await driver.toggleWiFi();
            }
        }catch(err){
            console.log(err);
        } 
    }

I think the issue is if the connection type is 6 even if state is true then the else if code is being executed.

Answer 1

Dave Newton's answer was what I was after. I needed to stick the connType checks in brackets see below:

async setWiFiConnection(state){
        try{
            var connType = await driver.getNetworkConnection();
            if(state == true && connType != 2 && connType != 6){
                await driver.toggleWiFi();
            }else if(state == false && (connType == 2 || connType == 6)){
                await driver.toggleWiFi();
            }
        }catch(err){
            console.log(err);
        } 
    }

Thanks Dave