打印出表格中特定元素的列表

Question

I have two list x=[1,2,5,4,3] y=[4,8,9,2,18] and a .csv table that looks like the one below.

ID	Age	Group	Name
1	4	3	Sam
2	50	1	Raj
3	18	9	John

My goal is to print a list of Group for elements that are in (x,y) and (Id,Age) . So for example: Since (1,4) is in (x,y) and also in (Id,Age) , the list would contain 3 . For (3,18) would be a similar case as it is in both (x,y) and (Id, Age) . So then my result would be a list of these numbers, [3,9] .

I tired doing result=df[df['ID'].isin(x), df['Age'].isin(y)]['Group'] but this get me anywhere. I am stuck on what to do next. Any help would appreciated.

Answer 1

What you try to do seems to be an AND , that is done with

df[df['ID'].isin(x) & df['Age'].isin(y)]

But with that data

df = pd.DataFrame([{'ID': 1, 'Age': 4, 'Group': 3, 'Name': 'Sam'},
                   {'ID': 2, 'Age': 50, 'Group': 1, 'Name': 'Raj'},
                   {'ID': 3, 'Age': 18, 'Group': 9, 'Name': 'John'},
                   {'ID': 3, 'Age': 19, 'Group': 9, 'Name': 'John'}])
x = [1, 2, 5, 4, 3]
y = [4, 8, 9, 19, 18]

It would give also the (3, 19) line even is that isn't a pair

   ID  Age  Group  Name
0   1    4      3   Sam
2   3   18      9  John
3   3   19      9  John

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You need to look by row, here's some try

pairs = list(zip(x, y))
result = df[pd.Series(zip(df['ID'], df['Age'])).isin(pairs)]['Group']