正则表达式提取 2 个正斜杠后面的字符，但忽略两个正斜杠（和后面的文本）是否在双引号之间

Question

I am working with some string manipulation where I have a multiline text and have to extract text that follows //, but if // (and text) are between double quotes then match should not happen. A sample of the text I am working with is below:

This a line // tester 7897
//Ola
asdfasdf
//554654
Open("asd//Not this")

From the above text I'm expecting the intended Regex to return me the following matches

// tester 7897
//Ola
//554654

I have tried quite a few options but the following regex (with Regex Options Multiline) is the closest I have got to is following one:

(//).+

This gives me all matches following // and that includes //Not this from the last line (which I don't want).

I don't have a lot of experience using Regex. Any help will be greatly appreciated.

Answer 1

I do not think this is possible. You want to match everything after // only if it is not surrounded by "" . That would require negative lookaround, and you cannot use negative lookbehind in this case where the number of characters between the first " and // is not fixed.

Answer 2

Try this.

^(?:[^\"\n]|\\\")*(?:(?<!\\)\"(?:[^\"\n]|\\\")*(?:(?<!\\)\")(?:[^\"\n]|\\\")*)*((?:\/\/).*)

Here is the link for regex101 .

Here is the reference .