堆栈内存溢出
  简体   繁体   English

按前 10 个字符拆分列表中的字符串，Python

[英]Splitting strings in a list by the first 10 characters, Python

 原文  2021-06-23 15:03:01  7   3    python/ list/ split

问题描述

I am trying to get the ASIN number for each product on Amazon which is the first ten digits after dp/.我正在尝试获取亚马逊上每个产品的 ASIN 编号，即 dp/ 之后的前十位数字。 I have gotten to the point where I have the digits but still have the junk after it.我已经到了我有数字但后面仍然有垃圾的地步。 Any help?有什么帮助吗？

   product_lst = [
            "https://www.amazon.com/Bentgo-Kids-Prints-Camouflage-5-Compartment/dp/B07R2CNSTK/ref=zg_bs_toys-and-games_home_2?_encoding=UTF8&psc=1&refRID=S3ESVW604M2GF8VYYVAZ",
            "https://www.amazon.com/Hamdol-Inflatable-Swimming-Sprinkler-Full-Sized/dp/B08SLYY1WD/?_encoding=UTF8&smid=AYKJMONAWDIKA&pf_rd_p=287d7433-71c6-4904-99b3-55833d0daaa0&pd_rd_wg=lMKJu&pf_rd_r=CR8F460JV643467SAG8Q&pd_rd_w=KgWnp&pd_rd_r=0e298b4a-6e52-4688-87bb-482fb6c1a56b&ref_=pd_gw_deals",
            "https://www.amazon.com/Fire-TV-Stick-4K-with-Alexa-Voice-Remote/dp/B079QHML21?ref=deals_primeday_deals-grid_slot-5_21f9_dt_dcell_img_0_ca4a9dae",
            "https://www.amazon.com/dp/B089RDSML3",
            "https://www.amazon.com/Lucky-Brand-Burnout-Notch-Shirt/dp/B081J8SGH7/ref=sr_1_2?dchild=1&pf_rd_i=7147441011&pf_rd_m=ATVPDKIKX0DER&pf_rd_p=e6aa97f3-9bc4-42c5-ac38-37844f71b469&pf_rd_r=S2F3A95JN2FDGBQ4V048&pf_rd_s=merchandised-search-9&pf_rd_t=101&qid=1624427428&s=apparel&sr=1-2"
        ]
for url in product_lst:
    product_lst = url.split("dp/")
    for url in product_lst:
        del product_lst[::2]
    print(product_lst)

Output:输出：

['B07R2CNSTK/ref=zg_bs_toys-and-games_home_2?_encoding=UTF8&psc=1&refRID=S3ESVW604M2GF8VYYVAZ'] ['B08SLYY1WD/? ['B07R2CNSTK/ref=zg_bs_toys-and-games_home_2?_encoding=UTF8&psc=1&refRID=S3ESVW604M2GF8VYYVAZ'] ['B08SLYY1WD/? encoding=UTF8&smid=AYKJMONAWDIKA&pf_rd_p=287d7433-71c6-4904-99b3-55833d0daaa0&pd_rd_wg=lMKJu&pf_rd_r=CR8F460JV643467SAG8Q&pd_rd_w=KgWnp&pd_rd_r=0e298b4a-6e52-4688-87bb-482fb6c1a56b&ref =pd_gw_deals']编码= UTF8＆SMID = AYKJMONAWDIKA＆pf_rd_p = 287d7433-71c6-4904-99b3-55833d0daaa0＆pd_rd_wg = lMKJu＆pf_rd_r = CR8F460JV643467SAG8Q＆pd_rd_w = KgWnp＆pd_rd_r = 0e298b4a-6e52-4688-87bb-482fb6c1a56b＆REF = pd_gw_deals']
['B079QHML21?ref=deals_primeday_deals-grid_slot-5_21f9_dt_dcell_img_0_ca4a9dae'] ['B089RDSML3'] ['B081J8SGH7/ref=sr_1_2?dchild=1&pf_rd_i=7147441011&pf_rd_m=ATVPDKIKX0DER&pf_rd_p=e6aa97f3-9bc4-42c5-ac38-37844f71b469&pf_rd_r=S2F3A95JN2FDGBQ4V048&pf_rd_s=merchandised-search-9&pf_rd_t=101&qid=1624427428&s=apparel&sr=1-2'] [ 'B079QHML21？REF = deals_primeday_deals-grid_slot-5_21f9_dt_dcell_img_0_ca4a9dae'] [ 'B089RDSML3'] ['B081J8SGH7 / REF = sr_1_2？dchild = 1＆pf_rd_i = 7147441011＆pf_rd_m = ATVPDKIKX0DER＆pf_rd_p = e6aa97f3-9bc4-42c5-ac38-37844f71b469＆pf_rd_r = S2F3A95JN2FDGBQ4V048＆pf_rd_s =商品化-搜索 - 9&pf_rd_t=101&qid=1624427428&s=服装&sr=1-2']

3 个解决方案

解决方案1
 4 已采纳  2021-06-23 15:09:36

For searches in text the module re (regex) is a good choice:对于文本搜索，模块re (regex)是一个不错的选择：

product_lst = [
"https://www.amazon.com/Bentgo-Kids-Prints-Camouflage-5-Compartment/dp/B07R2CNSTK/ref=zg_bs_toys-and-games_home_2?_encoding=UTF8&psc=1&refRID=S3ESVW604M2GF8VYYVAZ",
"https://www.amazon.com/Hamdol-Inflatable-Swimming-Sprinkler-Full-Sized/dp/B08SLYY1WD/?_encoding=UTF8&smid=AYKJMONAWDIKA&pf_rd_p=287d7433-71c6-4904-99b3-55833d0daaa0&pd_rd_wg=lMKJu&pf_rd_r=CR8F460JV643467SAG8Q&pd_rd_w=KgWnp&pd_rd_r=0e298b4a-6e52-4688-87bb-482fb6c1a56b&ref_=pd_gw_deals",
"https://www.amazon.com/Fire-TV-Stick-4K-with-Alexa-Voice-Remote/dp/B079QHML21?ref=deals_primeday_deals-grid_slot-5_21f9_dt_dcell_img_0_ca4a9dae",
"https://www.amazon.com/dp/B089RDSML3",
"https://www.amazon.com/Lucky-Brand-Burnout-Notch-Shirt/dp/B081J8SGH7/ref=sr_1_2?dchild=1&pf_rd_i=7147441011&pf_rd_m=ATVPDKIKX0DER&pf_rd_p=e6aa97f3-9bc4-42c5-ac38-37844f71b469&pf_rd_r=S2F3A95JN2FDGBQ4V048&pf_rd_s=merchandised-search-9&pf_rd_t=101&qid=1624427428&s=apparel&sr=1-2"
]

import re

results = []
for url in product_lst:
    m = re.search(r"/dp/([^/?]+)",url)
    if m:
        results.append(m.groups()[0])
print(results)

Output:输出：

['B07R2CNSTK', 'B08SLYY1WD', 'B079QHML21', 'B089RDSML3', 'B081J8SGH7']

I use r"/dp/([^/?]+)" as pattern wich boils down to a grouped match for anything after /dp/ and then matches all things up to the next / or ?我使用r"/dp/([^/?]+)"作为模式，归结为/dp/之后任何内容的分组匹配，然后将所有内容匹配到下一个/或? . .

You can test regexes online - I use http://regex101.com (for complex ones) - it can even provide python code based on what you insert in its fields (not using that though ;o) )您可以在线测试正则表达式 - 我使用http://regex101.com （对于复杂的） - 它甚至可以根据您在其字段中插入的内容提供 python 代码（虽然不使用它；o））

You can change your own code to您可以将自己的代码更改为

for url in product_lst:
    part = url.split("dp/")
    if len(part) > 1:            # blablubb dp/ more things => 2 or more parts
        print(part[1])           # print whats is left after dp/

to avoid overwriting your list product_lst - but you will still need to trim stuff after / and ?避免覆盖您的列表product_lst - 但您仍然需要在 / 和 ? with it.用它。

解决方案2
 1  2021-06-23 15:12:01

After you split() on the 'dp/' , there is absolutely no reason to loop.在'dp/'上split()之后，绝对没有理由循环。 You know exactly where the data is that you want, so just get it directly:你确切地知道你想要的数据在哪里，所以直接获取它：

   product_lst = [
            "https://www.amazon.com/Bentgo-Kids-Prints-Camouflage-5-Compartment/dp/B07R2CNSTK/ref=zg_bs_toys-and-games_home_2?_encoding=UTF8&psc=1&refRID=S3ESVW604M2GF8VYYVAZ",
            "https://www.amazon.com/Hamdol-Inflatable-Swimming-Sprinkler-Full-Sized/dp/B08SLYY1WD/?_encoding=UTF8&smid=AYKJMONAWDIKA&pf_rd_p=287d7433-71c6-4904-99b3-55833d0daaa0&pd_rd_wg=lMKJu&pf_rd_r=CR8F460JV643467SAG8Q&pd_rd_w=KgWnp&pd_rd_r=0e298b4a-6e52-4688-87bb-482fb6c1a56b&ref_=pd_gw_deals",
            "https://www.amazon.com/Fire-TV-Stick-4K-with-Alexa-Voice-Remote/dp/B079QHML21?ref=deals_primeday_deals-grid_slot-5_21f9_dt_dcell_img_0_ca4a9dae",
            "https://www.amazon.com/dp/B089RDSML3",
            "https://www.amazon.com/Lucky-Brand-Burnout-Notch-Shirt/dp/B081J8SGH7/ref=sr_1_2?dchild=1&pf_rd_i=7147441011&pf_rd_m=ATVPDKIKX0DER&pf_rd_p=e6aa97f3-9bc4-42c5-ac38-37844f71b469&pf_rd_r=S2F3A95JN2FDGBQ4V048&pf_rd_s=merchandised-search-9&pf_rd_t=101&qid=1624427428&s=apparel&sr=1-2"
        ]
for url in product_lst:
    split_lst = url.split("dp/")
    print(split_lst[1][:10]

I assume that the ASIN is always 10 characters.我假设 ASIN 总是 10 个字符。 Adjust the splice if there are more characters and it is always fixed.如果有更多字符，请调整拼接，它始终是固定的。 Otherwise you will need to find a different appproach.否则，您将需要找到不同的方法。

解决方案3
 0  2021-06-23 15:35:16

You can directly get the ASIN without splitting the data.无需拆分数据即可直接获取ASIN。

product_lst = [
            "https://www.amazon.com/Bentgo-Kids-Prints-Camouflage-5-Compartment/dp/B07R2CNSTK/ref=zg_bs_toys-and-games_home_2?_encoding=UTF8&psc=1&refRID=S3ESVW604M2GF8VYYVAZ",
            "https://www.amazon.com/Hamdol-Inflatable-Swimming-Sprinkler-Full-Sized/dp/B08SLYY1WD/?_encoding=UTF8&smid=AYKJMONAWDIKA&pf_rd_p=287d7433-71c6-4904-99b3-55833d0daaa0&pd_rd_wg=lMKJu&pf_rd_r=CR8F460JV643467SAG8Q&pd_rd_w=KgWnp&pd_rd_r=0e298b4a-6e52-4688-87bb-482fb6c1a56b&ref_=pd_gw_deals",
            "https://www.amazon.com/Fire-TV-Stick-4K-with-Alexa-Voice-Remote/dp/B079QHML21?ref=deals_primeday_deals-grid_slot-5_21f9_dt_dcell_img_0_ca4a9dae",
            "https://www.amazon.com/dp/B089RDSML3",
            "https://www.amazon.com/Lucky-Brand-Burnout-Notch-Shirt/dp/B081J8SGH7/ref=sr_1_2?dchild=1&pf_rd_i=7147441011&pf_rd_m=ATVPDKIKX0DER&pf_rd_p=e6aa97f3-9bc4-42c5-ac38-37844f71b469&pf_rd_r=S2F3A95JN2FDGBQ4V048&pf_rd_s=merchandised-search-9&pf_rd_t=101&qid=1624427428&s=apparel&sr=1-2"
             ]

ASIN=[]
for url in product_lst:
    idx = url.find("/dp/")
    ASIN.append(url[idx+4:idx+14])

print(ASIN)

output输出

['B07R2CNSTK', 'B08SLYY1WD', 'B079QHML21', 'B089RDSML3', 'B081J8SGH7']

暂无
暂无

声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

相关问题 在python中拆分整个字符串列表 - splitting whole list of strings in python 在python中搜索和分割带有特殊字符的字符串 - Searching and splitting strings with special characters in python 使用特定字符在Python中拆分字符串 - Splitting strings in Python using specific characters Python - 如何迭代列表中字符串的第一个字符 - Python - how to iterate over the first characters of strings in a list python拆分和重新组合列表的字符串 - python splitting and re-combining strings of a list Python，使用正则表达式在具有重叠匹配项的中间字符上拆分字符串 - Python, splitting strings on middle characters with overlapping matches using regex 按 Python 中的特定字符串/部分字符串拆分列表 object - Splitting list object by specific strings/part of the strings in Python 在某些字符后分割字符串 - splitting strings after certain characters 在列表中分割字符串 - splitting a strings inside a list 拆分列表中的字符串 - Splitting Strings In List
相关标签
 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM