我们如何通过在 javascript 中使用正则表达式转义撇号来选择两个单引号之间的字符串？

Question

Example Text: 'builder's margin' means the percentage stated in Item 8 of Schedule 1;

Here I have a regex that selects words between two single quotes /'(.*?[^\\\\])'/g . But it's not working when i try to extract builder's margin from the example text because there is apostrophe so it's only selecting up to builder . so is there any way that we can escape apostrophe and select up to margin??

Answer 1

Assuming the middle apostrophe has no word character right after it, you can try this regex:

'(?:\\.|'(?=\w)|[^'])*'

RegEx Demo

RegEx Details:

• ' : Start opening '
• (?: : Start non-capture group
  • \\\\. : Match \\ and an escaped character
  • | : OR
  • '(?=\\w) : Match ' if it has a word character next to it
  • | : OR
  • [^'] : Match any character that is not '
• )* : End non-capture group. Repeat this group 0 or more times
• ' : Closing '

Answer 2

If you do not need to support escape sequences (ie if your string is not a string literal presented as plain text), you can use

(?!\b'\b)'([^']*(?:\b'\b[^']*)*)(?!\b'\b)'

Else, if the text you have can contain escape sequences, you can use

(?!\b'\b)'([^'\\]*(?:(?:\\.|\b'\b)[^'\\]*)*)(?!\b'\b)'

See the regex demo #1 and regex demo #2 .

NOTE : replace . with [^] to match any chars including line break chars.

Details

• (?!\\b'\\b)' - the ' char that is not enclosed with word chars on both ends
• ([^']*(?:\\b'\\b[^']*)*) - Capturing group 1:
  • [^']* - zero or more chars other than '
  • (?:\\b'\\b[^']*)* - zero or more occurrences of a ' not enclosed with word chars and then zero or more chars other than '
• ([^'\\\\]*(?:(?:\\\\.|\\b'\\b)[^'\\\\]*)*) - Group 1 (in the second pattern):
  • [^'\\\\]* - zero or more chars other than ' and \\
  • (?:(?:\\\\.|\\b'\\b)[^'\\\\]*)* - zero or more sequences of a \\ + any one char or a ' that is enclosed with word chars and then zero or more chars other than ' and \\
• (?!\\b'\\b)' - the ' char that is not enclosed with word chars on both ends

Answer 3

Try

'(.+?)'\B

which basically means ' , then some content, then ' , followed by a non-word char.

 a = `normal 'quoted' string` b = `'builder's margin' means the percentage` c = `this 'we'll handle'` re = /'(.+?)'\\B/ console.log(a.match(re)[1]) console.log(b.match(re)[1]) console.log(c.match(re)[1])

Note that this doesn't handle trailing apostrophes as in 'builders' margins' are...