将两个不同大小的元组列表合并到一个字典列表中

Question

Now I have two lists of tuples of different size like this:

a = [('NC', 0, 'Eyes'),('NC', 3, 'organs'),('NC', 19, 'neurons'),...]
b = [(0, 'Hypernym', 3),(19, 'Holonym', 0),...]

The common values from the above lists is the int number, and the expected result should look like:

result = [
    {'s_type':'NC', 's':'Eyes', 'predicate':'Hypernym', 'o_type':'NC', 'o':'organs'},
    {'s_type':'NC', 's':'neurons', 'predicate':'Holonym', 'o_type':'NC', 'o':'Eyes'},
    ...]

I have converted the above two lists into dictionaries and tried nested loop but failed to get this output. Can somebody kindly help me out?

Answer 1

I managed to get this one working. Let me know if there are any other specifics that need fixing.

a = [('NC', 0, 'Eyes'), ('NC', 3, 'organs'), ('NC', 19, 'neurons')]
b = [(0, 'Hypernym', 3), (19, 'Holonym', 0)]

result = []

for s_type, common, s in a:
    related = list(filter(lambda x: x[0] == common, b))
    for o_type, predicate, next in related:
        next_related = list(filter(lambda x: x[1] == next, a))
        for s_type, _, organ in next_related:
            result.append({'s_type': s_type, 's': s,
                           'predicate': predicate, 'o_type': o_type, 'o': organ})

print(result)

I hope this is what you were looking for. There are many other ways to do this, but given your description of the problem, this should do.