如果列表具有所有值，如何返回 None 作为 None else 以有效的方式返回列表中的真值

Question

I have a mix of True , False , None in a list. If I have all values as None in the list eg ListA=[None, None, None] I will have to return None . Otherwise, If I have a mix of boolean values and None eg ListA=[True, True, False, None] . I need to return True for this list because it has one True .

Is there another efficient way to write this logic?

my code so far is:

any[listA] if list_A != None then None

Answer 1

You can try the below code:

my_list=[True,None, None, None]

if(any(my_list)):
    print("True")
else:
    print("None")

returns None if all items of my_list are None.if not returns True.

Using any() is by far the faster and effective alternative.

Answer 2

Try this code.

is_bool_or_none = lambda some_list: True if (True in [type(element) == bool for element in some_list]) else None
print(is_bool_or_none(your_list_here))