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如何在添加元素之前检查队列 ( LinkedList ) 中是否存在元素?

[英]How do I check if an element exists in a queue ( LinkedList ) before adding it?

How do I check if an element exists in a queue ( LinkedList ) before adding it ?如何在添加元素之前检查队列 (LinkedList) 中是否存在元素?

EX: Address [id=1, url=https://www.google.com, size=2, queue=[request [requestId=1], request [requestId=2]]] EX:地址 [id=1, url=https://www.google.com, size=2, queue=[request [requestId=1], request [requestId=2]]]

I can't add queue=[request [requestId=1], request [requestId=1]] because they have the same requestId.我无法添加 queue=[request [requestId=1], request [requestId=1]] 因为它们具有相同的 requestId。

you can use contains(Object o) method你可以使用contains(Object o)方法

contains description:包含描述:

Returns true if this list contains the specified element.如果此列表包含指定元素,则返回 true。 More formally, returns true if and only if this list contains at least one element e such that (o==null ? e==null : o.equals(e)).更正式地说,当且仅当此列表包含至少一个元素 e 满足 (o==null ? e==null : o.equals(e)) 时,才返回 true。 [...] [...]

Parameters: o – element whose presence in this list is to be tested参数: o – 要测试其在此列表中的存在的元素

Returns: true if this list contains the specified element返回:如果此列表包含指定元素,则为 true

LinkedList implements the Collection interface, which defines the Collection#contains method. LinkedList实现了Collection接口,该接口定义了Collection#contains方法。

You can do what you're after with any class that derives from Collection easily by just using the contains method.只需使用contains方法,您就可以轻松地使用从Collection派生的任何类来完成您所追求的事情。

See the docs on LinkedList#contains for more information.有关详细信息,请参阅LinkedList#contains上的文档。

Note: It uses Objects#equals to determine if the item is in the Collection .注意:它使用Objects#equals来确定该项目是否在Collection中。

If you have the same reference, I think you'll be good.如果你有相同的参考,我想你会很好。 If you have different references representing the same data, then you may need to @Override the equals method on your object.如果您有代表相同数据的不同引用,那么您可能需要@Override对象上的equals方法。

Below code may help you...下面的代码可以帮助你...

package com.example.Solution;

import java.util.LinkedList;
import java.util.Queue;

public class Sol {
    public static void main(String[] args){
        Queue<Address> q1= new LinkedList<>();
        q1.add(new Address("abc",1,"url1"));
        Address a1=new Address("abc",1,"url");
        if(!q1.contains(a1))
            q1.add(a1);
        Address a2=new Address("abc",2,"url");
        if(!q1.contains(a2)){
            q1.add(a2);
        }
        Address a3=new Address("abc",1,"url2");
        if(!q1.contains(a3)){
            q1.add(a3);
        }
        System.out.println(q1.size());
    }
}
class Address {
    String name;
    int id;
    String url;

    public Address(String name, int id, String url) {
        this.name = name;
        this.id = id;
        this.url = url;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getUrl() {
        return url;
    }

    public void setUrl(String url) {
        this.url = url;
    }
    public boolean equals(Object o1){
        Address address=(Address) o1;
        return address.getId()==this.id;
    }
}

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