如何使用 get() 在 CakePhp 3 中获取给定 ID 的所有关联数据？

Question

Here is my situation....

1. I can view item details based on item ID passed from GUI

   public function view($id = null){ $id = $this->request->getData('assetsource_id'); $assetSource = $this->AssetSources->get($id, [ 'contain' => ['Assets'] ]); debug($assetSource); die(); $this->set('assetSource', $assetSource); $this->set('_serialize', ['assetSource']);

2. When I debug, I get the following except...

    /src/Controller/AssetSourcesController.php (line 64) object(App\\Model\\Entity\\AssetSource) { 'id' => (int) 18, 'name' => 'Donated', 'created_by' => '', 'assets' => [ (int) 0 => object(App\\Model\\Entity\\Asset) { 'id' => (int) 1, 'school_unit_id' => (int) 33, 'asset_source_id' => (int) 18, 'asset_description' => 'TOYOTA HILUX', 'date_of_entry' => object(Cake\\I18n\\FrozenDate) { 'time' => '2021-05-31T00:00:00+00:00', 'timezone' => 'UTC', 'fixedNowTime' => false }, 'date_of_purchase' => object(Cake\\I18n\\FrozenDate) { 'time' => '2021-05-31T00:00:00+00:00', 'timezone' => 'UTC', 'fixedNowTime' => false }, 'grn_number' => 'KBHBBH92', 'name_of_supplier' => 'TOYOTA ZAMBIA', 'serial_number' => 'YTDIYTFYUFOGOOHH', 'location' => 'BURSAR', 'asset_category_id' => (int) 24, 'asset_group_class_id' => (int) 65, 'full_asset_number' => 'GGFUYG88', 'condition_id' => (int) 12, 'asset_status_id' => (int) 14, 'value' => '400,000', 'custodian_name' => 'JOE BANDA', 'custodian_phone' => '0966010101', 'custodian_email' => 'bursar@unza.zm', 'created' => object(Cake\\I18n\\FrozenTime) { 'time' => '2021-05-31T07:26:31+00:00', 'timezone' => 'UTC', 'fixedNowTime' => false }, 'modified' => object(Cake\\I18n\\FrozenTime) { 'time' => '2021-05-31T07:26:31+00:00', 'timezone' => 'UTC', 'fixedNowTime' => false }, 'created_by' => 'admin', '[new]' => false, '[accessible]' => [ '*' => true, 'id' => false ], '[dirty]' => [], '[original]' => [], '[virtual]' => [], '[errors]' => [], '[invalid]' => [], '[repository]' => 'Assets' } ], '[new]' => false, '[accessible]' => [ '*' => true, 'id' => false ], '[dirty]' => [], '[original]' => [], '[virtual]' => [], '[errors]' => [], '[invalid]' => [], '[repository]' => 'AssetSources' }

3. Except when I pass the result to the view.ctp, school_unit_id , asset_source_id , asset_category_id , asset_group_class_id , condition_id , asset_status_id are showing the corresponding IDs as saved in Assets table.

    <?php foreach ($assetSource->assets as $assets) : ?> <tr> <td><?php echo $i++ ?></td> <td><?= h($assets->school_unit_id) ?></td> <td><?= h($assets->asset_description) ?></td> <td><?= h($assets->date_of_purchase) ?></td> <td><?= h($assets->name_of_supplier) ?></td> <td><?= h($assets->location) ?></td> <td><?= h($assets->condition_id) ?></td> <td><?= h($assets->value) ?></td> <td><?= h($assets->custodian_name) ?></td> </tr> <?php endforeach; ?>

4. How do I show the respective display fields instead of IDs? Notice asset_sources table is only associated to assets table. Then assets table is associated to school_units , asset_sources , asset_categories , asset_group_classes , conditions , asset_status tables. In my view. I want to see school_unit_name not school_unit_id . NOTE: I used bake commands to create the application.

Thanks

Answer 1

Read up on containment. It will let you include whatever you want. 'contain' => ['Assets' => ['SchoolUnits']] should work here, and then you can use $assets->school_unit->name or something like that in your view.