Django 将参数列表传递给 url

Question

In my dhango project i create a function callable via url:

url(r'^pd/(?P<c_id>[\w\-]+)\/$', calc_q),

So my function need to manage at least 4 input

@csrf_exempt
def calc_q(request, c_id):

    start_d = datetime.date(2021, 6, 28)
    end_d = datetime.date(2021, 6, 29)
    v_id = 17
    q_time ="15min"
    ...

How can i pass, for example a list or a dict from url to my function with my 4 variables inside? Is possible pass all variables directly in url? Whitch is the best method?

So many thanks in advance

Answer 1

You can do that in the following manner :

urls.py

url(r'^pd/(?P<c_id>[\w\-]+)\(?P<value>\d+)/$', calc_q)

then in your template

<a href="{% url 'name_url' value=0 %}">my link</a>

In your view:

@csrf_exempt
def calc_q(request, c_id, value):

    start_d = datetime.date(2021, 6, 28)
    end_d = datetime.date(2021, 6, 29)
    v_id = 17
    q_time ="15min"
    ...