如何制作自定义不和谐机器人@某人，某人在命令中@ed？

Question

When I type !best it comes up with my username which also does it if I @ someone else with the same command like !best @example and comes up with @nottheexample

if message.content.startswith('!best'):
        await message.channel.send(message.author.mention)

Answer 1

To mention a user you have to define it beforehand. You do this as follows:

user = message.mentions[0]

To mention the user you can either use f -strings or format .

Based on the code above here is an example:

@client.event # Or whatever you use
async def on_message(message):
    user = message.mentions[0]
    if message.content.startswith('!best'):
        await message.channel.send("Hello, {}".format(user.mention))

Please note that the code only works if you then also specify a user . However, you can add more if or else statements if you want to handle it differently.

Answer 2

message.author.mention always mentions the author of the message

you can solve this in multiple ways

1. Just send whatever comes behind !best

if message.content.startswith('!best'):
    args = message.content.split('!best ')
    if len(args) > 1:
        await message.channel.send(args[1])
    else:
        await message.channel.send(message.author.mention)

2. same as number 1, but add some check if the thing behind !best is a real member - see Utility Functions in the docs

member = discord.utils.find(lambda m: m.name == args[1], message.guild.members)

member = discord.utils.get(message.guild.members, name=agrs[1])

3. Use Commands - I really recommend this one

from discord.ext import commands

bot = commands.Bot(command_prefix='!')

@bot.command()
async def best(ctx, member: discord.Member = None):
    if member is None:
        member = ctx.author
    await ctx.send(member.mention)