将一个 bash 脚本中的 output 视为另一个 bash 脚本中的文件

Question

There are a few questions on this site phrased similarly, but none quite get at what I need.

I have a script that processes data from some file, in a manner something like...

infile=$1
grep foo $infile
#process line(s) containing "foo"
grep bar $infile
#process line(s) containing "bar"
grep yyy $infile
grep zzz $infile
#process together lines containing yyy and zzz

My question is, I would like for infile to be replaced with the output from another script. I would rather not store the output in a temporary file. How do I do this? Is there a way? I thought about a named pipe but when I do that the script hangs after the first grep command (which, at least, is successful). I haven't been able to find any other way.

Answer 1

The command to do that is awk :

infile=$1
awk '
  /foo/ { #process line(s) containing "foo"}
  /bar/ { #process line(s) containing "bar"}
  /yyy/ && /zzz/ { #process together lines containing yyy and zzz}
' $infile