如何在 Python 中公开 S3 存储桶中的对象图像？

Question

I'm trying to set my Object I have in my S3 Bucket to Public which I can do manually by selecting 'Make Public' option which allows 'Read' access within the Object ACL which works fine since it displays the image on my webpage fine, my question is what python code would I have to use to allow this 'Read' access within the ACL to allow my image to be public?

I have tried generating a policy which didn't work, I set the whole bucket to public which still didn't allow the image to be public aswell. So unsure what Python code would allow this.

#!/usr/bin/env python3
import sys
import boto3
ec2 = boto3.resource('ec2', region_name = 'eu-west-1')
s3 = boto3.resource('s3')
keyname = 'key2.pem'
user_data = '''#!/bin/bash
yum update -y
yum install httpd -y
systemctl enable httpd
systemctl start httpd'''
s3.create_bucket(ACL='private',Bucket='ec2-buket1',CreateBucketConfiguration={'$
sg = ec2.create_security_group(GroupName='webServer', Description = 'WebServer'$


response = sg.authorize_ingress(
    IpPermissions=[
        {
            "FromPort": 22,
            "ToPort": 22,
            "IpProtocol": "tcp",
            "IpRanges": [
                {"CidrIp": "0.0.0.0/0", "Description": "WebServer"},
            ],
        },
        {
            "FromPort": 80,
            "ToPort": 80,
            "IpProtocol": "tcp",
            "IpRanges": [
                {"CidrIp": "0.0.0.0/0", "Description": "WebServer"},
            ],
        },
    ],
)

instance = ec2.create_instances(
 ImageId='ami-64ecf1b725342da',
 MinCount=1,
 MaxCount=1,
 InstanceType='t2.nano',
 KeyName = 'key2.pem',
 UserData = user_data, 
 SecurityGroupIds=[sg.group_id] 
)
for bucket_name in sys.argv[1:]:
 try:
         response = s3.create_bucket(Bucket=ec2-assignbuke2,
CreateBucketConfiguration={'LocationConstraint': 'eu-west-1'})
         print (response)
 except Exception as error:
         print (error)

def upload_to_s3(filename, bucket, key):
  try:
    response = s3.Object(bucket, key).put(Body=open(filename, 'lr'))
    print (response)
    return response
  except Exception as error:
    print (error)

file = 'image1.jpg'
bkt = 'ec2-bucket1'
key = 'image1.jpg'
rsp = upload_to_s3(file, bkt, key)

object_acl = s3.ObjectAcl('bucket2','image1.jpg')

response = object_acl.put(
    ACL='public-read',
    AccessControlPolicy={
        'Grants': [
            {
                'Grantee': {
                    'BucketName': 'bucket2',
                    'Key' : 'image1.jpg'
                },
                'Permission': 'READ'
            },
        ],
     }
    GrantRead='string',
    GrantReadACP='string',
    VersionId='string',
)

Answer 1

最干净的方法是将 ACL 指定为上传的一部分：

s3_resource.Bucket(bucket_name).upload_file(filename, key, ExtraArgs={'ACL': 'public-read'})