如何在 HTML 中找到标签的数量

Question

I have an html that looks like this:

 <h3>First</h3>
<ol>
    <li>
        First list

        <ol>
            <li>First Sub list</li>
        </ol>
    </li>
</ol>
<h3>Second</h3>
<ol>
    <li>
        second list
        <ol>
            <li>First Sub list</li>
            <li>second sub list</li>
        </ol>
    </li>
    <li>
        second in second list
        <ol>
            <li>First Sub list</li>
            <li>second sub list</li>
        </ol>
    </li>
</ol>

I need to be able to get count of li tags that appear within ol tag after each h3. So the result will 1 2

I am using this statement to calculate count

print(len(h3_soup1.find_next("ol").find_all("li")))

But this gives me count of all the li tags within ol tag. For instance for the first one it says 2 and for 2nd it says 6.

Edit:

For the first ol output should be 1 For second ol it should be 2 So print for each ol

Edit:

The final goal is to find length of these li tags. And if this length is greater than a certain number then remove the last tags. For instance if length shouldn't be greater than 1 then the second list will become:

<h3>First</h3>
<ol>
    <li>
        First list

        <ol>
            <li>First Sub list</li>
        </ol>
    </li>
</ol>
<h3>Second</h3>
<ol>
    <li>
        second list
        <ol>
            <li>First Sub list</li>
            <li>second sub list</li>
        </ol>
    </li>

</ol>

Answer 1

Filter ol.children .

from bs4 import BeautifulSoup

data = '''\
<h3>First</h3>
<ol>
    <li>
        First list

        <ol>
            <li>First Sub list</li>
        </ol>
    </li>
</ol>
<h3>Second</h3>
<ol>
    <li>
        second list
        <ol>
            <li>First Sub list</li>
            <li>second sub list</li>
        </ol>
    </li>
    <li>
        second in second list
        <ol>
            <li>First Sub list</li>
            <li>second sub list</li>
        </ol>
    </li>
</ol>
'''

soup = BeautifulSoup(data, 'html.parser')

for ol in soup.select('h3 + ol'):
    print(
        len([e for e in ol.children
             if type(e) == type(ol) and e.name == 'li']))