REGEX 在两个字符之间获取第 N 个单词

Question

I am trying to get a regex to use in Data Studio, what I am trying to do is be able to pull out the following into custom fields so I would need 4 regex's for each one

STRING = first_Product (21) » second_Product_3 (64) » third_Product (53) » fourth_Product_4 (21)

into .

custom_field_1 = first_product.

custom_field_2 = second_product.

custom_field_3 = third_product.

custom_field_4 = fourth_product.

To get the first I am using

.+?(?=\()

To get the second one I am able to use

    \»(.*?)\( 

Would anyone be able to helo with this

Answer 1

You could use a regex with a quantifier like {2} {3} to get the specific matches from capture group 1.

^(?:(?:^|»\s+)(.*?)\s*\(\d+\)(?:\s+|$)){2}

The pattern matches:

• ^ Start of string
• (?: Non capture group to match as a whole part
  • (?:^|»\\s+) Assert the start of the string or match » and 1+ whitespace chars
  • (.*?) Capture group 1 , match 1+ times any char as least as possible
  • \\s*\\(\\d+\\) Match optional whitespce chars and 1+ digits between parenthesis
  • (?:\\s+|$) Match either 1+ whitespace chars or assert the end of the string
• ){2} Close the non capture group and repeat n times (in this example 2 times)

Regex demo