Javascript正则表达式匹配跳回新行

Question

So I have this string:

function abc() {\n\n    return def;\n}

And I use this:

string.match(/[^\r\n]+/g)

And it matches into 3 lines:

Match 1: function abc() {

Match 2: return def;

Match 3: }

But it is missing a fourth match which should be the new line with no characters after the '{'.

I am using the website https://regex101.com/r/ALvFIN/1/ to test.

Set to flavor: ECMAScript

Regex: /[^\\r\\n]+/g

Test String:

function abc() {

    return def;
}

Any idea how to correctly match the double \\n\\n with no characters on line 2? I have tried the whitespace \\s and \\S but not right. Starting to think I need to look at an alternative solution.

Answer 1

You seem to want to match a string of one or more non-linebreak chars or an empty line.

This logic means you simply want to split a string with a single line break sequence .

To match ASCII line breaks, CRLF, LF or CR, you can use /\\r\\n?|\\n/ .

To match any Unicode line break sequence, you can use /\\r\\n|[\\r\\n\\f\\…\
\
]/ .

 console.log("function abc() {\\n\\n return def;\\n}".split(/\\r\\n?|\\n/)) // Any Unicode line break sequence: var rx = /\\r\\n|[\\r\\n\\f\\…\
\
]/; console.log("function abc() {\\n\\n return def;\\n}".split(rx))

And if you still want to use .match() simply add a ^$ alternative to your regex with /m flag to make ^ and $ match start/end of a line:

 console.log("function abc() {\\n\\n return def;\\n}".match(/[^\\r\\n]+|^$/gm))

Answer 2

If you want to split the string into its constituent lines, you can use this: /^.*$/gm . Note the m option to enable multiline matching.