如何在python的列表中显示以下程序的输出？

Question

numbers=[int(input("Number ( " + str(i+1) + " ) : ")) for i in range(int(input("How many numbers do you want to add ?")))]
for nums in numbers:
    new=[]
    if 10<nums and nums<100:
        new.append(nums)
        print(new)

if you insert 3 numbers like : 124 , 12 , 14 the answer will be : [12] [14] but I want : [12 , 14] thank you :)

Answer 1

numbers = [int(input("Number ( " + str(i + 1) + " ) : ")) for i in
           range(int(input("How many numbers do you want to add ?")))]

new = []  # This must be outside the loop
for nums in numbers:
    if 10 < nums < 100:
        new.append(nums)
print(new)

Answer 2

You're defining the new = [] array inside the for loop, which is causing the creation of a new array every iteration.

Your code should look like this:

 numbers=[int(input("Number ( " + str(i+1) + " ) : ")) for i in range(int(input("How many numbers do you want to add ?")))] new = [] for nums in numbers: if 10<nums and nums<100: new.append(nums) print(new)