[英]use rm linux order in execl() function ic C language
hope to be fine... i'm trying write code that use execl within execl in C language but it's not working when i put the directory of file.希望一切顺利...我正在尝试编写在 C 语言的 execl 中使用 execl 的代码,但是当我放置文件目录时它不起作用。 the code is:代码是:
#include<stdio.h>
#include<unistd.h>
#include<stdlib.h>
#include<sys/wait.h>
int main(int argc,char* argv[]){
int n,m,x;
n=fork();
if(n==0){
execl("/bin/rm","rm /home/mazenas/Desktop/folder/","f.txt",NULL);
}
else{
wait(&m);
printf("end of Programm\n");
}
return 0;
}
help me plaese!帮帮我吧!
The arguments of execl()
is specifying the command-line arguments of the program to be executed. execl()
的参数指定要执行的程序的命令行参数。
execl("/bin/rm","rm /home/mazenas/Desktop/folder/","f.txt",NULL);
means to execute this:意味着执行这个:
"rm /home/mazenas/Desktop/folder/" "f.txt"
If you want to execute this command:如果要执行此命令:
rm "/home/mazenas/Desktop/folder/f.txt"
You should write:你应该写:
execl("/bin/rm", "rm", "/home/mazenas/Desktop/folder/f.txt", NULL);
I'm pretty sure you mean我很确定你的意思是
execl("/bin/rm","rm", "/home/mazenas/Desktop/folder/f.txt",NULL);
If rm
checks its invocation name, then f.txt
makes no sense and it complains;如果rm
检查其调用名称,则f.txt
没有意义并且它会抱怨; otherwise it's going to try to rm f.txt
in the current directory rather than the given path.否则它将尝试在当前目录而不是给定路径中 rm f.txt
。
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