Python 调用带参数的 shell 脚本

Question

I have a shell script I need to call from a Python script. Only thing is that is needs to pass 7 parameters, that are basically variables, and some of those contain spaces.

I see a lot of references to os.system, and to subprocess, but what about the parameters with spaces? I think those will cause an issue.

Answer 1

Edit 2:

subject = "Proposal"
to = "LandonStatis@stackoverflow.com"
from = "Joshua@stackoverflow.com"
REPORT_DIRECTORY = "/home/reports"
file = "/home/files/proposal.txt"
message = "Please accept me as the best answer"

#i didnt include the "flag" because i dont know the flag format

os.system('./home/scripts/send_email.pl "'+subject+'" "'+to+'" "'+from+'" "'+REPORT_DIRECTORY+'" "'+file+'" "'+message+'"')

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Edit:

If you want to add a variable, you can do so like this

os.system('ls -al '+str(x))

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For example, if your username is "landon statis" with a space,

you can do this: os.system('ls -al "/home/landon statis/Desktop"')

(notice the space in the command above?)

This works for both Windows and Linux.

Use double quotes to prevent word splitting. An argument enclosed in double quotes presents itself as a single word, even if it contains whitespace separators.

This is the source, which is a link to Linux Documentation Project. Check them out, it's very useful: Advanced Bash Scripting Guide: Chapter 5 - Quoting

Answer 2

Please do not use os.system or subprocess with shell=True . Both execute a shell and are potentially vulnerable to shell injections. See https://docs.python.org/3/library/subprocess.html#security-considerations for more details.

Best way is to use subprocess and hand it a list of arguments. Example: Let's just use a Shell script that print its arguments. myscript :

#!/bin/sh
for arg in "$@"; do
   echo "argument: $arg"
done

Then you can call this script using a list as argument:

subprocess.run(["./myscript", "first", "argument with space", "third"])

Output:

argument: first
argument: argument with space
argument: third