无法在linux中执行文件

Question

I have created a program in which fopen() is being used. For Ex:-

int main() {
    FILE* check=NULL;
    check=fopen("C:\\Files\\open.txt","rb");
    if(check==NULL)
    {
        cout<<"Error";
    }
    else
    {
        //do something
    }
    
}

Now, in the above program windows path is working properly ie "C:\\\\Files\\\\open.txt" but when i try to execute the same program in wsl(linux) by changing the path to /mnt/c/Files/open.txt , I am getting error. I am not sure if setting up path this way is the standard procedure for fopen() in linux. Please suggest me something to overcome this error.

Answer 1

Try adding perror("fopen") to the main function and please share the output. It is difficult to answer this question without the output.

I think the problem may be: You don't have permission to access /mnt or no such file or that file doesn't have read permission... etc.