复制对象（无堆）

Question

Consider the following piece of code

class A{
  public:
     int val;
     a(); 
}
int main(){
     A obj1;
     A obj2=obj1;
}

In this case, there are no pointers or heap involved. Will this A obj2=obj1 be shallow copy or deep copy? When I use addressof() function on obj1 and obj2 I get different values.

Answer 1

There's actually no such thing as a shallow copy here, because copying an object of type A will always copy val .

But with a class like this:

class B
{
    char *s;
};

you can make either a shallow copy or a deep copy, depending on whether you copy just the pointer s (shallow), or whether a copy is made of what s is pointing to (deep). In the case of a deep copy, the value of s is different in the copy, of course, because it ends up pointing at a different chunk of memory to the original.