对于具有 void 返回类型的函数，从 int 到 int* 的无效转换错误

Question

So, I need to get the maximum value from an array. So the first input line contains the number of array elements, then the values for the array. But I am really confused as to why this error keeps popping up when I pass an integer type array to the function. I am finding it a little difficult to deal with pointers and functions at the moment.

#include<iostream>
using namespace std;
void maxim(long long int nums[],long long int n){
    int max_val=0;
    for(int i=0;i<n;i++){
        if(nums[i]>max_val){
            max_val=nums[i];
        }
    }
    cout<<max_val<<endl;
}
int main() {
    long long int n;
    cin>>n;
    long long int arr[n];
            for(int i=0;i<n;i++){
        cin>>arr[i];
    }
    maxim(arr[n],n);
    return 0;
}

Answer 1

#include<iostream>
using namespace std;
void maxim(long long int *nums,long long int n){
    long long int max_val=nums[0];
    for(int i=1;i<n;i++){
        if(nums[i]>max_val){
            max_val=nums[i];
        }
    }
    cout<<max_val<<endl;
}
int main() {
    long long int n;
    long long int *arr;
    cin>>n;
    arr = new long long int[n];
    for(int i=0;i<n;i++){
        cin>>arr[i];
    }
    maxim(arr,n);
    delete []arr;
    return 0;
}