C#中匹配字符串中的!WSⅡ%^ OR WSⅡ的正则表达式

Question

How do I match alpahbet with roman symbol following with regular expressions.如何使用正则表达式将字母表与罗马符号匹配。

I have got #!WSⅡ%^ WSⅡ ancient data =>(should match both WSⅡ)我有#!WSⅡ%^ WSⅡ古代数据=>（应该匹配两个WSⅡ）
I have got #!WSⅡ%^ @#WSⅡ WSⅡ ancient data =>(should match 3 times)我有#!WSⅡ%^@#WSⅡWSⅡ古代数据=>（应该匹配3次）
I have got AbWSⅡ WSⅡRR WSⅡ ancient data =>(should match 1 time) (AbWSⅡ WSⅡRR should not match)我有AbWSⅡ WSⅡRR WSⅡ古代数据=>（应该匹配1次）（AbWSⅡ WSⅡRR应该不匹配）

I am using the following regular expression.我正在使用以下正则表达式。

(?<![a-zA-Z0-9])(\\bWSⅡ\\b)(?=[a-zA-Z0-9]|) (?<![a-zA-Z0-9])(\\bWSⅡ\\b)(?=[a-zA-Z0-9]|)

Which is working for my all the cases except the above.除上述情况外，这适用于我的所有情况。

Note : Ⅱ is not II注：Ⅱ不是Ⅱ

Please help.请帮忙。

Thanks in advance提前致谢

Answer 1

You can use您可以使用

(?<![^\W_])WSⅡ(?![^\W_])

The regex matches正则表达式匹配

(?<![^\\W_]) - a negative lookbehind that matches a location that is not immediately preceded with a char other than a non-word and _ char (so it basically requires start of string or a non-word char or _ right before) (?<![^\\W_]) - 一个负向后视匹配一个位置，该位置前面不是非单词和_字符以外的字符（因此它基本上需要字符串开头或非单词字符或_就在之前）
WSⅡ - a WSⅡ word WSⅡ - 一个WSⅡ字
(?![^\\W_]) - a negative lookahead that matches a location that is not immediately followed with a char other than a non-word and _ char (so it basically requires end of string or a non-word char or _ right after). (?![^\\W_]) - 匹配一个位置的负向前瞻，该位置后面没有紧跟非单词和_字符以外的字符（因此它基本上需要字符串结尾或非单词字符或_紧随其后）。