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Django - 通过 related_query_name 获取对象

[英]Django - get objects by related_query_name

I have the following Model at my models.py to store genre information for specific objects at my Database like Movies for example:我的models.py中有以下模型,用于在我的数据库中存储特定对象的类型信息,例如电影:

class Genre(models.Model):
    objects = RandomManager()
    id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False)
    content_type = models.ForeignKey(ContentType, limit_choices_to=referential_genre_models, on_delete=models.CASCADE, verbose_name=_("Content Type"))
    object_id = models.CharField(max_length=36, verbose_name=_("Object ID"))
    content_object = GenericForeignKey('content_type', 'object_id')
    name = models.CharField(verbose_name=_("Genre"), blank=True, null=True, editable=False, max_length=50)
    date_added = models.DateTimeField(auto_now_add=True, verbose_name=_("Date Added"))

At my Movies model class I have the following field to connect the two models with each other:在我的电影模型类中,我有以下字段可以将两个模型相互连接:

genre_relation = GenericRelation(Genre, related_query_name='genre_relation')

At my views.py I now want to query onto specific Movies of genre "Comendy" and "Family" for example, but I don't get back any results:例如,在我的 views.py 中,我想查询流派“Comendy”和“Family”的特定电影,但我没有得到任何结果:

movie_genre_assets = Movies.objects.get_queryset().filter(Q(genre_relation__name="Comedy") | Q(genre_relation__name="Family")).order_by('release_date')

Can smb.可以help?帮助?

Rather than a GenericRelation you should use a through table .您应该使用直通表而不是 GenericRelation。 This is a separate model with a foreign key to both Movie and Genre and each record forms a relation.这是一个单独的模型,具有指向 Movie 和 Genre 的外键,并且每个记录形成一个关系。

class Movie(models.Model):
    genre = models.ManyToManyField(through="MovieGenre")
    ...

class Genre(models.Model):
    ...

class MovieGenre(models.Model):
    movie = models.ForeignKey(Movie, on_delete=models.CASCADE)
    genre = models.ForeignKey(Genre, on_delete=models.CASCADE)

You can then access the movies belonging to a genre with:然后,您可以通过以下方式访问属于某个类型的电影:

movie.genre.all()

And all the genres belonging to a move with:以及属于一个动作的所有流派:

genre.movie_set.all()

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