如何修改列表元素？

Question

I have two python lists:

name = ['Beijing']
alphabet = ['a', 'b', 'c']

I need to add each element of alphabet to the element in name such that output is :

new_name = ['Beijinga', 'Beijingb', 'Beijingc']

Can someone please help me with this?

Answer 1

You can use string concatenation with list comprehension:

name = ['Beijing']
alphabet = ['a', 'b', 'c']
new_name=[name[0]+x for x in alphabet]
print(new_name)

If there are multiple elements:

name = ['Beijing']
alphabet = ['a', 'b', 'c']
new_name=[names+x for names in name for x in alphabet]
print(new_name)

Answer 2

name = ['Beijing'] alphabet = ['a', 'b', 'c'] new_name = [name[0]+i for i in alphabet]

Answer 3

You can try in the following example.

import string
name = 'Beijing'
new_nam = [name + item for item in string.ascii_lowercase]

Output:

['Beijinga', 'Beijingb', 'Beijingc', 'Beijingd', 'Beijinge', 'Beijingf', 'Beijingg', 'Beijingh', 'Beijingi', 'Beijingj', 'Beijingk', 'Beijingl', 'Beijingm', 'Beijingn', 'Beijingo', 'Beijingp', 'Beijingq', 'Beijingr', 'Beijings', 'Beijingt', 'Beijingu', 'Beijingv', 'Beijingw', 'Beijingx', 'Beijingy', 'Beijingz']

Answer 4

If you are a beginner at Python this code may help you.

names = ['Beijing']
alphabet = ['a', 'b', 'c']

newName = []

for name in names:
    for letter in alphabet:
        newName.append(f"{name}{letter}")

Answer 5

In your example, you have only one name . Assuming you will have many names , I have a solution (It would work for single names too) -

name = ['Beijing','QWERTY']
alphabet = ['a', 'b', 'c']

new_lst = []
for j in name:
    for i in alphabet:
        new_lst.append(j+i)

Result :

['Beijinga', 'Beijingb', 'Beijingc', 'QWERTYa', 'QWERTYb', 'QWERTYc']

Or, you could use a list comprehension which is better and makes it easier -

new_lst = [j+i for j in name for i in alphabet]
print(new_lst)

Answer 6

If you have two lists of arbitrary size, you can use itertools.product() to do this quite easily:

>>> import itertools
>>> name = ['Beijing']
>>> alphabet = ['a', 'b', 'c']
>>> new_name = list(map(''.join, itertools.product(name, alphabet)))
>>> new_name
['Beijinga', 'Beijingb', 'Beijingc']