是否有从 python 数据帧创建行列表的函数？

Question

s1 = pd.Series([5, 6, 7])
s2 = pd.Series([7, 8, 9])

df = pd.DataFrame([list(s1), list(s2)],  columns =  ["A", "B", "C"])

   A  B  C
0  5  6  7
1  8  9  1

and I need : [5,6,7,8,9,1]

Is there a function that does this directly?

Answer 1

您可以随时将数据帧转换为 numpy 数组并解开：

df.to_numpy().ravel()

Answer 2

Just stack the dataframe which will create single columnar series, then call tolist()

>>> df.stack().to_list()
[5, 6, 7, 8, 9, 1]

Answer 3

如果你不想使用 numpy，这里有一个替代方案：

df.T.melt()['value'].to_list()

Answer 4

You can just do

import numpy as np
np.ravel(df).tolist()

Answer 5

I will assume that your output was typed in incorrectly. Here is my take on the output. Unfortunately, it's not "one function".

result = [x for y in df.itertuples(False) for x in y]

Answer 6

Try converting it too a list.

import numpy

numpy.ravel(df).tolist()