[英]Delete an object from an array of objects inside an Object
I am not sure how to form this question, but I will do my best.我不确定如何形成这个问题,但我会尽力而为。 I want to remove an object from an array
produits
that is inside the parent object, depending on the families.name
that must equal a string from the initial object that I want to delete ( I already achieved this part).我想从数组中删除一个对象
produits
即父对象内,这取决于families.name
即必须等于从我想要删除的初始对象的字符串(I已经达到了这个部分)。
Right now I'm stuck and don't know how to update the initial Parent
object, I was able to delete the object from the array produits.现在我卡住了,不知道如何更新初始
Parent
对象,我能够从数组产品中删除该对象。
The parent Object:父对象:
let Parent = {
"Id": "60f03c42a512e04c4b0161e7",
"familles": [{
"name": "LOV D+",
"parent": "QB",
"produits": [{
"uid": "ITEM-20210715-20758",
"type": "fabricant",
"parent_uid": null,
"version_application": "1.1.0",
"creation_date": null,
"titu": "REST1",
"ref_cstb": "162367462",
"gamme": "SUPERGRES",
"serie": "PREMIERE",
"description": "300x300 - 20 - Blue",
"usines": null
},
{
"uid": "QB32N-20210720-75584",
"type": "fabricant",
"parent_uid": null,
"version_application": "1.1.0",
"creation_date": "2021-07-20T14:34:04.49Z",
"titu": "REST1",
"ref_cstb": "ref-18-taieb",
"gamme": "SUPERGRES T_20",
"serie": "WIND",
"description": null,
"usines": null
}
],
"version_schema": null
},
{
"name": "LOV F+",
"parent": "QB",
"produits": [{
"uid": "ITEM-20210720-33547",
"type": "fabricant",
"parent_uid": null,
"version_application": "1.1.0",
"creation_date": "2021-07-20T14:46:37.649Z",
"titu": "REST1",
"ref_cstb": "ref19-taieb",
"gamme": "SUPERGRES T_20",
"serie": "STOCKHOLM",
"description": null,
"usines": null
}],
"version_schema": null
}
]
}
The object I want to delete我要删除的对象
let obj1 = {
"uid": "ITEM-20210715-20758",
"type": "fabricant",
"parent_uid": null,
"version_application": "1.1.0",
"creation_date": null,
"titu": "REST1",
"ref_cstb": "162367462",
"gamme": "SUPERGRES",
"serie": "PREMIERE",
"description": "300x300 - 20 - Blue",
"usines": null,
"group": "QB - LOV D+",
"parent": "QB"
}
So that my Parent Object will look like this这样我的父对象看起来像这样
let Parent = {
"Id": "60f03c42a512e04c4b0161e7",
"familles": [{
"name": "LOV D+",
"parent": "QB",
"produits": [{
"uid": "ITEM-20210720-75584",
"type": "fabricant",
"parent_uid": null,
"version_application": "1.1.0",
"creation_date": "2021-07-20T14:34:04.49Z",
"titu": "REST1",
"ref_cstb": "ref-18-taieb",
"gamme": "SUPERGRES T_20",
"serie": "WIND",
"description": null,
"usines": null
}],
"version_schema": null
},
{
"name": "LOV F+",
"parent": "QB",
"produits": [{
"uid": "ITEM-20210720-33547",
"type": "fabricant",
"parent_uid": null,
"version_application": "1.1.0",
"creation_date": "2021-07-20T14:46:37.649Z",
"titu": "REST1",
"ref_cstb": "ref19-taieb",
"gamme": "SUPERGRES T_20",
"serie": "STOCKHOLM",
"description": null,
"usines": null
}],
"version_schema": null
}
]
}
What I have so far done:到目前为止我所做的:
Remove(obj, parentObj) {
let a = e.group.split("-").pop().slice(1)
console.log(a) // Will Display LOV D+
let newArray = this.certificat.familles.find((x: {
name: any;
}) => x.name === a); // Will display the proper object that have the name = LOV D+
newArray = newArray.produits.filter(({
uid
}) => {
return uid !== e.uid;
}); // This will delete the object from the array, but it will not update the parent object, I'm missing something here
}
Remove(obj1, parent)
Here you go.干得好。 This will splice the object with matching
name
and uid
from Parent
, like you want.这将拼接具有匹配
name
和来自Parent
uid
的对象,如您所愿。
let Parent = { "Id": "60f03c42a512e04c4b0161e7", "familles": [{ "name": "LOV D+", "parent": "QB", "produits": [{ "uid": "ITEM-20210715-20758", "type": "fabricant", "parent_uid": null, "version_application": "1.1.0", "creation_date": null, "titu": "REST1", "ref_cstb": "162367462", "gamme": "SUPERGRES", "serie": "PREMIERE", "description": "300x300 - 20 - Blue", "usines": null }, { "uid": "QB32N-20210720-75584", "type": "fabricant", "parent_uid": null, "version_application": "1.1.0", "creation_date": "2021-07-20T14:34:04.49Z", "titu": "REST1", "ref_cstb": "ref-18-taieb", "gamme": "SUPERGRES T_20", "serie": "WIND", "description": null, "usines": null } ], "version_schema": null }, { "name": "LOV F+", "parent": "QB", "produits": [{ "uid": "ITEM-20210720-33547", "type": "fabricant", "parent_uid": null, "version_application": "1.1.0", "creation_date": "2021-07-20T14:46:37.649Z", "titu": "REST1", "ref_cstb": "ref19-taieb", "gamme": "SUPERGRES T_20", "serie": "STOCKHOLM", "description": null, "usines": null }], "version_schema": null } ] } let obj1 = { "uid": "ITEM-20210715-20758", "type": "fabricant", "parent_uid": null, "version_application": "1.1.0", "creation_date": null, "titu": "REST1", "ref_cstb": "162367462", "gamme": "SUPERGRES", "serie": "PREMIERE", "description": "300x300 - 20 - Blue", "usines": null, "group": "QB - LOV D+", "parent": "QB" } function Remove(obj, parentObj) { let famille = parentObj.familles.findIndex((x) => x.name === obj.group.split(" - ").pop()); let produit = parentObj.familles[famille].produits.findIndex((x) => x.uid === obj.uid); parentObj.familles[famille].produits.splice(produit, 1); } Remove(obj1, Parent); console.log(Parent);
let Parent = { "Id": "60f03c42a512e04c4b0161e7", "familles": [{ "name": "LOV D+", "parent": "QB", "produits": [{ "uid": "ITEM-20210715-20758", "type": "fabricant", "parent_uid": null, "version_application": "1.1.0", "creation_date": null, "titu": "REST1", "ref_cstb": "162367462", "gamme": "SUPERGRES", "serie": "PREMIERE", "description": "300x300 - 20 - Blue", "usines": null }, { "uid": "QB32N-20210720-75584", "type": "fabricant", "parent_uid": null, "version_application": "1.1.0", "creation_date": "2021-07-20T14:34:04.49Z", "titu": "REST1", "ref_cstb": "ref-18-taieb", "gamme": "SUPERGRES T_20", "serie": "WIND", "description": null, "usines": null } ], "version_schema": null }, { "name": "LOV F+", "parent": "QB", "produits": [{ "uid": "ITEM-20210720-33547", "type": "fabricant", "parent_uid": null, "version_application": "1.1.0", "creation_date": "2021-07-20T14:46:37.649Z", "titu": "REST1", "ref_cstb": "ref19-taieb", "gamme": "SUPERGRES T_20", "serie": "STOCKHOLM", "description": null, "usines": null }], "version_schema": null } ] } let obj1 = { "uid": "ITEM-20210715-20758", "type": "fabricant", "parent_uid": null, "version_application": "1.1.0", "creation_date": null, "titu": "REST1", "ref_cstb": "162367462", "gamme": "SUPERGRES", "serie": "PREMIERE", "description": "300x300 - 20 - Blue", "usines": null, "group": "QB - LOV D+", "parent": "QB" } function filterParent(obj, parentObj) { let a = obj.group.split("-").pop().slice(1) let newArray = parentObj.familles.map((x) => x.name !== a ? x : {...x, produits:x.produits.filter(matchUID)}); function matchUID(produit){ return produit.uid !== obj.uid } return {...parentObj, familles:newArray} } Parent = filterParent(obj1, Parent) console.log(Parent)
can't understamd your question properly but if you want to manually remove array then use无法正确理解您的问题,但如果您想手动删除数组,请使用
delete Parent.familles[0].produits[0]
删除 Parent.familles[0].produits[0]
delete keyword to delete and then path of array to delete. delete 关键字要删除,然后是要删除的数组的路径。
You can search for the index of the particular element/object and then delete it using您可以搜索特定元素/对象的索引,然后使用
delete Parent.familles[0].produits[0]
删除 Parent.familles[0].produits[0]
const fruits = ["Banana", "Orange", "Apple", "Mango"]; console.log(fruits.indexOf("Apple"))
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