如何从一个整数列表和一个布尔值列表创建一个列表？ （Python）

Question

eg suppose I have two lists:

list1 = [1,2,3,4,5,6]
list2 = [False,True,False,True,False,False]

How can i create the list below (only using items in list1 that correspond to false in list2 by index position?

list3 = [1,3,5,6]

Thanks

Answer 1

Use .zip

list1 = [1,2,3,4,5,6]
list2 = [False,True,False,True,False,False]
list3=[j for i,j in zip(list2,list1) if i==False]
print(list3)

Answer 2

list1 = [1,2,3,4,5,6]
list2 = [False,True,False,True,False,False]
list3=[]
for i in range(0,len(list1)):
    if list2[i] == False:
        list3.append(list1[i])

Answer 3

Just use Boolean Logic and list comprehensions:

list1 = [1,2,3,4,5,6]
list2 = [False,True,False,True,False,False]
print([i[0] for i in zip(list1,list2) if not i[1]])    # this just includes an element if that element's corresponding value in the second list is False

This outputs:

[1, 3, 5, 6]

Answer 4

list1 = [1,2,3,4,5,6]
list2 = [False,True,False,True,False,False]

list3=[]

for i in range(len(list1)):
    if list2[i]==False:
        list3.append(list1[i])

Answer 5

list1 = [1,2,3,4,5,6]
list2 = [False,True,False,True,False,False]
output = list (map (lambda x,y: x if y == False else '', list1,list2))
while '' in output:
    output.remove('')
print(output)

Outputs [1, 3, 5, 6]