在 XMLHttpRequest 完成后运行 then 方法

Question

I have a method acting like an async method. After the request sends to the function that was called this request, I want to run something like the then method but then there is no then method for XMLHttpRequest. the caller function in below code has no then method

      let result = dataService.exportfile('get', '/api/overtimeedari/exporttoexcle/', model).
                then(() => {
                        self.loading(false);//غیرفعال کردن حالت لود  شدن گرید
                        buttonListSearch.Excel.loading(false); //غیرفعال کردن حالت لود شدن دکمه اکسل
                    });

the function called

        function exportfile(mehtodtype, url, model) {
            debugger;
            var qs = "?";
            model.map((item) => {
                qs = `${qs}${item.name}=${item.value}&`;
            });

            var request = new XMLHttpRequest();
            request.open(mehtodtype, url + qs, true);
            request.setRequestHeader('Authorization', "Bearer " + window.localStorage.getItem('token'));
            request.responseType = 'blob';
            request.onload = function (e) {
                if (this.status === 200) {
                    var blob = this.response;
                    if (window.navigator.msSaveOrOpenBlob) {
                        window.navigator.msSaveBlob(blob, fileName);
                    }
                    else {
                        var downloadLink = window.document.createElement('a');
                        var contentTypeHeader = request.getResponseHeader("Content-Type");
                        downloadLink.href = window.URL.createObjectURL(new Blob([blob], { type: contentTypeHeader }));
                        downloadLink.download = "Export.xls";
                        document.body.appendChild(downloadLink);
                        downloadLink.click();
                        document.body.removeChild(downloadLink);
                    }
                }
            };
            request.send();
            return request;
        }

Answer 1

Given the constraint of not changing exportfile function as per comment

the case is I don't have this ability to change the exportfile function because it has side affects on other functions

the best way to handle this is as follows

let req = dataService.exportfile('get', '/api/overtimeedari/exporttoexcle/', model);
req.addEventListener('loadend', () => {
  // do what's needed here
});

since exportfile returns the XMLHttpRequest object, you can listen for the loadend event and do whatever it you're doing there

Note, the loadend event is triggered regardless of success or failure

You could do the above with the load event if you want too - but, I'm unsure what order

x.onload=() => {};
x.addEventListener('load', () => {});

are fired ... also note, do NOT

req.onload=() => {};

since that would overwrite the onload callback inside the function