从 JSON 对象中删除空数据

Question

I have a Typescript class in which I collect a JSON Object with some empty parameters, what I want is to filter that object to obtain another Object but without the empty data of the first one.

This is my JSON object:

{ Country: 'Colombia',
  Ser: 'ok',
  Ins: '',
  BBDD: 'ok',
  Mid: '',
  Ata: '',
  'Branch Ser': 'ok',
  Service: '' }

This is what I want to achieve:

{ Country: 'Colombia',
      Ser: 'ok',
      BBDD: 'ok',
      'Branch Ser': 'ok' }

Answer 1

 const allData = { Country: 'Colombia', Ser: 'ok', Ins: '', BBDD: 'ok', Mid: '', Ata: '', 'Branch Ser': 'ok', Service: '' }; const filteredData = Object.entries(allData).reduce((x, [k, v]) => { if (v) { // not ( null, undefined, empty string) x[k] = v; } return x; }, {} as any); console.log(filteredData);

You can use Object.entries function to list object as key value pairs and then use the Array.reduce to filter out the falsy values.

Answer 2

 const allData = { Country: 'Colombia', Ser: 'ok', Ins: '', BBDD: 'ok', Mid: '', Ata: '', 'Branch Ser': 'ok', Service: '' }; const filteredData = Object.fromEntries(Object.entries(allData).filter(([_, value]) => value)); console.log(filteredData);

Above is a simple one-line solution to do it. Using JS' Object.fromEntries() really helps.