[英]How to get instance variable of a class list by using a class method?
sorry if it is a too easy question but I am just a beginner in python and watching some tutorial videos on classes.抱歉,如果这是一个太简单的问题,但我只是 Python 的初学者,正在观看一些有关课程的教程视频。 I tried to add something by myself but couldn't.我试图自己添加一些东西,但不能。 Here is the code :这是代码:
class Dog:
dogs = []
def __init__(self, name):
self.name = name
self.dogs.append(self)
@classmethod
def num_dogs(cls):
return len(cls.dogs)
@classmethod
def dogs_names(cls):
for i in cls.dogs:
return cls.dogs[i.name]
@staticmethod
def bark(n):
"""barks n times"""
for _ in range(n):
print("Bark! ")
tim = Dog("Tim")
jim = Dog("Jim")
print(Dog.num_dogs())
print(Dog.dogs_names())
So I know dogs_names() method looks dumb, but I hope you understand my point.所以我知道 dog_names() 方法看起来很愚蠢,但我希望你明白我的意思。 I can reach the dogs list by only returning cls.dogs each time but how do I reach name variables of each item in the list?我可以通过每次只返回 cls.dogs 来访问狗列表,但是如何访问列表中每个项目的名称变量?
Thank you for your help.谢谢您的帮助。
You can do :你可以做 :
class Dog:
dogs = []
def __init__(self, name):
self.name = name
self.dogs.append(self)
@classmethod
def num_dogs(cls):
return len(cls.dogs)
@classmethod
def dogs_names(cls):
names = [] # create a new list
for i in range(len(cls.dogs)):
names.append(cls.dogs[i].name) # append each name one by one to the list
return names # return the full list at the end
@staticmethod
def bark(n):
"""barks n times"""
for _ in range(n):
print("Bark! ")
tim = Dog("Tim")
jim = Dog("Jim")
print(Dog.num_dogs())
print(Dog.dogs_names())
you can also use list conprehension :您还可以使用列表理解:
@classmethod
def dogs_names(cls):
return [dog.name for dog in cls.dogs]
There are two things wrong:有两点不对:
i
is an instance of Dog
, so i.name
is a dog name, not an index in to the list of Dog
indices. i
是Dog
一个实例,所以i.name
是狗的名字,而不是Dog
索引列表中的索引。You build the list first, then return it after the loop is done building the list.您首先构建列表,然后在循环完成构建列表后返回它。
@classmethod
def dogs_names(cls):
dog_names = []
for i in cls.dogs:
dog_names.append(i.name)
return dog_names
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.