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如何从php mysql数据库中获取数组格式的数据

[英]How to get data in array format in from php mysql database

I have the following function in PHP, I am trying to get array in a specific format mentioned below but to no success, I am selecting a specific column in the mysql table than contains a json value like我在 PHP 中有以下函数,我试图以下面提到的特定格式获取数组但没有成功,我在 mysql 表中选择了一个特定的列,而不是包含一个 json 值

{
    "lat": "-0.008668899503063161",
    "lng": "0.0025903204871857714"
}

This is the function这是功能

 function test()
    {

        $pdo = new PDO ("mysql:host=localhost;dbname=dbname","user", "secret");

        $statement=$pdo->prepare("SELECT test FROM merchants WHERE user_id = 1");
        $statement->execute();
        $data = array();
        while( $row = $statement->fetch(PDO::FETCH_ASSOC) )
        {
            $data[] = json_decode( $row['test'] );
        }


        return $data ;

    }

I am expecting the following result我期待以下结果

['lat' => -0.008668899503063161,'lng' => 0.0025903204871857714,]

But this is what I keep getting但这就是我不断得到的

[{"lat":"-0.008668899503063161","lng":"0.0025903204871857714"}]

Don't push onto an array if you just want a single value.如果您只想要一个值,请不要推送到数组。

function test()
{

    $pdo = new PDO ("mysql:host=localhost;dbname=dbname","user", "secret");

    $statement=$pdo->prepare("SELECT test FROM merchants WHERE user_id = 1");
    $statement->execute();
    row = $statement->fetch(PDO::FETCH_ASSOC) )
    if ($row) {
        $data = json_decode( $row['test'], true );
    } else {
        $data = null;
    }
    return $data ;
}

I managed to do it like this我设法这样做

 'merchants.location' =>
        [
              'lat' => $data['lat'],
              'lng' => $data['lng']

        ]

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