Python - 访问列表中的多个值

Question

I am sorry for not sharing detailed information, see below code *

import json
import requests
def funcname(): 
    response = requests.get('https:aig.com/e/id')
    parsed_response = json.loads(response.text)
    print(parsed_response)
    print(type(parsed_response))

If I run the above the code, I get the following output:

{'values': [{'id': '123456','name': 'person1'}, {'id': '-1123678','name': 'person2'},{'id': '566','name': 'person3'}, {'id': '-1123678','name': 'person4'},{'id': '-1123678','name': 'person5'}]}
<class 'dict'>

There are actually 100+ entries, I just listed these 5

I would like to create a python program to ask for input for person name and print the id based on name we give.

So, suppose if I prompted the user for a name of a person and user input person3 , the output should be the id 566

Unfortunately, the provided code is throwing an error.

Answer 1

You can construct a dictionary and index into it based on your input:

>>> myList = [{'id': '123','name': 'one'},{'id': '-1123','name': 'two'},{'id': '566','name': 'three'}]
>>> nameToId = dict((e['name'], e['id']) for e in myList)
>>> nameToId[input("Enter a name: ")]
Enter a name: two
'-1123'

Answer 2

you can try it:

myDict = {'values': [{'id': '123456','name': 'person1'}, {'id': '-1123678','name': 'person2'},{'id': '566','name': 'person3'}, {'id': '-1123678','name': 'person4'},{'id': '-1123678','name': 'person5'}]};


for i in range(len(myDict['values'])):
    if(myDict['values'][i]['name'] == 'person3'):
        print(myDict['values'][i]['id'])
    

or

myDict = {'values': [{'id': '123456','name': 'person1'}, {'id': '-1123678','name': 'person2'},{'id': '566','name': 'person3'}, {'id': '-1123678','name': 'person4'},{'id': '-1123678','name': 'person5'}]};
        
        
name = input("Enter name: \n")

for i in range(len(myDict['values'])):
    if(myDict['values'][i]['name'] == name):
        print(myDict['values'][i]['id'])

Answer 3

So you have your list

mylist = [{'id': '123','name': 'one'},{'id': '-1123','name': 'two'},{'id': '566','name': 'three'}]

Now, let's say you have defined a variable

myname = "one"

All you have to do is search for the corresponding id with that name:

[item["id"] for item in mylist if item["name"] == myname]

Answer 4

a = [{'id': '123','name': 'one'},{'id': '-1123','name': 'two'},{'id': '566','name': 'three'}]
name = input()
for i in a:
    if i['name'] == name:
        print(i['id'])
        break

Answer 5

Maybe too late for the party but here is my take with error message if name is not found in the list:

dict_arr = [{'id': '123','name': 'one'},{'id': '-1123','name': 'two'},{'id': '566','name': 'three'}]

def find_id(req_name):
    for dic in dict_arr:
        if dic['name'] == req_name:
            print(dic['id'])
            return

    #if name not found in list:
    print("Invalid name")
    return

if __name__ == "__main__":
    req_name = input("Enter name:\n")
    find_id(req_name)