将列表转换为字符串列表

Question

In Python, I have this list:

[(0, 0, 0), (0, 0, 1), (0, 1, 0), (0, 1, 1), (1, 0, 0), (1, 0, 1), (1, 1, 0), (1, 1, 1)]

and I want to convert it into a list of strings, like:

['000', '001', '010', '011', '100', '101', '110', '111']

This was my attempt:

val = [0,1]

['{x}{y}{z}'.format(x=x,y=y,z=z) for x in val for y in val for z in val]

But in some cases, the length of the string eg'001' may be variable (eg '01101') so it is frustrating editing this part '{x}{y}{z}'.format(x=x,y=y,z=z) each time

How can I do that?

Answer 1

Using for loops and concatenation:

arr1 = [(0, 0, 0), (0, 0, 1), (0, 1, 0), (0, 1, 1), (1, 0, 0), (1, 0, 1), (1, 1, 0), (1, 1, 1)]

arr2 = []
for ind in range(len(arr1)):
    arr2.append("")
    for n in arr1[ind]:
        arr2[ind] += str(n)

print(arr2)

While this is a very simple and readable approach, there are other ways to do this that take up less space and have slightly more complex implementations, such as @Olvin Roght's solution .

Answer 2

Here's the more simplifier version

a=[(0, 0, 0), (0, 0, 1), (0, 1, 0), (0, 1, 1), (1, 0, 0), (1, 0, 1), (1, 1, 0), (1, 1, 1)]
b=[]
for i in a:
    c=str(i)
    c=c.replace("(","")
    c=c.replace(")","")
    c=c.replace(",","")
    b.append(c)
print(b)

This would give you the exact same output as of @Aniketh Malyala 's answer