使用 Python 在远程服务器上解压缩 zip 文件

Question

I need to write Python code to login to remote server and navigate to Zip file path and then unzip & save on remote server. As a next step, I need to access the files inside the unzipped folder. Can anyone please help. I referred few links but unable to get complete solution. https://medium.com/@keagileageek/paramiko-how-to-ssh-and-file-transfers-with-python-75766179de73

Answer 1

First you can upload file using .put() and next you can use external program unzip to uncompress it.

Something similar to

import paramiko

# login
ssh_client = paramiko.SSHClient()
ssh_client.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh_client.connect(hostname='192.168.0.1', username='user', password='PaSsWoRd')

# upload
ftp_client = ssh_client.open_sftp()
ftp_client.put('local.zip', 'remote.zip')
ftp_client.close()

# unzip
stdin, stdout, stderr = ssh_client.exec_command('unzip remote.zip')
print(stdout.read().decode())

# access files
stdin, stdout, stderr = ssh_client.exec_command('ls')
print(stdout.read().decode())

---

If you want to put in subfolder then you may need to create this subfolder

stdin, stdout, stderr = ssh_client.exec_command('mkdir upload')

ftp_client.put('local.zip', 'upload/remote.zip')

stdin, stdout, stderr = ssh_client.exec_command('cd upload ; unzip remote.zip')

stdin, stdout, stderr = ssh_client.exec_command('ls upload')
# or 
stdin, stdout, stderr = ssh_client.exec_command('cd upload ; ls')